The largest possible sum with 2 six sided dice is 12.
There are 36 outcomes for rolling 2 dice, and there is 1 way that a 12 can occur which is 6,6. So, the probability of rolling the sum of 12 on 2 dice is 1/36.
The probability of rolling a sum of 11 with 2 dice is: P(11) = 1/18.For explanation see answer to question: "What is the probability of rolling 7 or 11 with 2 dice?".Read more: What_is_the_probability_of_rolling_7_or_11_with_2_dice
3 times (out of 36) is the probablility Possible Outcome 1 - Dice 1: 4, Dice 2: 6 Possible Outcome 2 - Dice 1: 5, Dice 2: 5 Possible Outcome 3 - Dice 1: 6, Dice 2: 4
There are 5 elements in the event space if you roll a sum of 8 with 2 dice; 2,6 & 6,2 & 3,4 & 4,3 & 4,4.
It is 5 over 6.
Prob(Sum is odd) = 1/2 Prob(Sum > 6) = 15/36 = 5/12 Prob(Sum is odd or >6) = 27/36 = 3/4
The probability is 26/36 = 13/18.
When 2 dice are rolled, the probability of getting a sum less than 4 or greater than 9 is 2 in 9. There are 36 permutations of two six sided dice, 1-1, 1-2, ..., 1-6, 2-1, ... 2-6, ..., 6-1, 6-2, ... 6-6. Of these permutations, 3 have a sum less than four, 1-1, 1-2, and 2-1, and 5 have a sum greater than nine, 4-6, 5-5, 5-6, 6-4, 6-5, and 6-6. Add these probabilities together and you get (3 + 5) in 36, or 8 in 36, or 2 in 9.
7/12 ≈ 0.583 Probability is number_of_ways_of_success/total_number_of_ways. There are 36 possible ways 2 dice can land when thrown. To be more than 6, the sum can be 7, 8, ..., 12 There is 1 way to achieve 12 (6 & 6); 2 ways to achieve 11 (5 & 6 and 6 & 5); ... 6 ways to achieve 7 (1 & 6, 2 & 5, ..., 6 & 1); A Total of 1 + 2 + ... + 6 = 21 ways of getting a sum greater than 6. Thus the probability of throwing a sum greater than 6 is 21/36 = 7/12.
There are 36 permutations of two dice. Of these, 6 have a sum less than five, 1+1, 1+2, 1+3, 2+1, 2+2, and 3+1. The probability, then, of rolling a sum less than five on two dice is 6 in 36, or 1 in 6, or about 0.1667.
The sum is greater than 24.
Prob(Rolling a number greater than 2) = 1 - Prob(Not rolling a number greater than 2 on either die) = 1 - Prob(Rolling a number less than or equal to 2 on both dice) = 1 - Prob(Rolling a number less than or equal to 2 on a die)2 = 1 - (1/3)2 = 8/9
There are 36 permutations of two dice. Only one of them has a sum of two. Then probability, then, of rolling a sum of more than two is 35 in 36, or about 0.9722.
3.5 and 7.9846 are two. Their sum is 11.4846 is greater than 1.
The probability is 5/36.
Assuming:you are rolling two six-sided dice:"greater than 5" does not include 5Number of possible rolls = 36 (6x6)28 rolls satisfy "at least one die shows a 4 or the sum of the dice is greater than 5":(1, 4), (1, 5), (1, 6),(2, 4), (2, 5), (2, 6),(3, 3), (3, 4), (3, 5), (3, 6),(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6),(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6),The probability that at least on die shows a 4 or that the sum of the dice is greater than 5 is 28/36, or 7/9, or approx. 77.8%