If factors include 1 and the number itself then the any number (n) with only 4 factors has to be the product of two prime numbers, p1 and p2.
The factors are then n, p1, p2, and 1.
The largest 3-digit number with only 4 factors is 998. The factors are 998, 499, 2 and 1
The largest one digit number that has three factors is 9. Its factors are 1, 3, and 9.
what is the largest three-digit number that is divisible by 4, 5, and 6
The largest number with three digits is 999.
999 is the largest 3 digit number because each of the three digits is the largest possible value (9). Whole number simply means that there is no decimal part or fraction.
999 = 27 x 37
The largest one digit number that has three factors is 9. Its factors are 1, 3, and 9.
The largest two-digit number that has exactly three factors is 99. A number has exactly three factors if it is the square of a prime number. In this case, ( 9 = 3^2 ) has three factors: 1, 3, and 9. However, since 99 is the largest two-digit number, we consider its factors, but it does not meet the criterion. The correct answer is 81, which is ( 9^2 ).
The largest two-digit number with exactly three factors is 99. A number has exactly three factors if it is the square of a prime number, specifically in the form ( p^2 ) where ( p ) is a prime. The only prime number whose square is a two-digit number is 7, since ( 7^2 = 49 ) and ( 11^2 = 121 ) exceeds two digits. Thus, 49 is the largest two-digit number with exactly three factors.
The only number that ONLY has two and five as factors is 10, which has two digits, so there are no numbers that are three digits long and ONLY have two and five for factors. However, if you are asking what the largest three digit number that has two and five for factors, it would be the largest three digit number with ten as a factor, as ten the the LCM of two and five, and that would be 390.
130, 260,390,520,650,780,910.1040. So the largest three digit number with factors of '5' & '13' is 910.
997
800 2x2x2x2x2x5x5
999 is the largest three-digit number that is divisible by 17. However, 986 is the largest three-digit number that is evenly divisible (no remainder) by 17. 986 / 17 = 58
The largest three-digit number is 999. To find the largest three-digit number divisible by 7, you can divide 999 by 7, which gives approximately 142.714. Multiplying 142 by 7 gives 994, so the largest three-digit number divisible by 7 is 994.
its 567
what is the largest three-digit number that is divisible by 4, 5, and 6
The largest number with three digits is 999.