I think the last digit would be 5
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To find the last digit of a number raised to a power, we can use the concept of cyclicity. The last digit of 445 is 5. When 5 is raised to any power, the last digit of the result will always be 5. Therefore, the last digit of 445 to the power of 12 will also be 5.
Oh, what a happy little question! Let's paint a picture with numbers. When you raise 445 to the power of 12, you'll find that the last digit is 5. Isn't that just a delightful little detail to discover?
12 is the only two digit number which is a factor of 12.
If 8 x divisor is 2 digit, divisor must be 12 or less If fist digit quotient x divisor is 3 digit, the first digit has to be 9 and the divisor is 12 9 x 12 = 108 8 x 12 = 96
To convert a number to scientific notation:write out the number starting with the first non-zero digit and continue until the last non-zero digit;put the decimal point after the first digit;count how many digits the decimal point needs to move to get back to where it was originally (if there was no decimal point as the number was a whole number it was "hiding" after the ones-digit, the last digit);if the decimal point need to move left make this count negative;write ×10 to the power of this count after the number written in step 2.For 0.0000000000073:737.3move decimal place 12 place to the leftIt's to the left, so count becomes -127.3 × 10⁻¹²0.0000000000073 = 7.3 × 10⁻¹²
i am a two digit # my tens digit# is 3 times my ones digit #and the sum of my digit is 12 what am i
Two digit no and the sum of the two digit give 12 39,48,57,66,75,84,93 are the possible two digit no whose sum is 12. Example 3+9=12;4+8=12...... Difference of the two digit no is 2 that is 57and75. because difference of 5 and 7 is 2. Next, unit digit to be greater than tens digit. So 57 is ans because 7 is in unit digit which is greater than tens digit.