6 A 'quarter'and 5 'one cents'
6 1*50 cents 2*20 cents 1*5 cents 1*2 cents and 1*1 cent. For cents (in a Euro).
Two Dime or 10 cents 10 x 2 = 20
6 - 2 quarters, 1 dime, 1 nickel, and 2 pennies, okay 5 if you have a 50-cent piece
No, you can't make 25 cents out of 22 coins
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6 A 'quarter'and 5 'one cents'
6 1*50 cents 2*20 cents 1*5 cents 1*2 cents and 1*1 cent. For cents (in a Euro).
The least amount would be 3 coins (half-dollar, dime, nickel) The most would be 65, all pennies.
Two Dime or 10 cents 10 x 2 = 20
6 - 2 quarters, 1 dime, 1 nickel, and 2 pennies, okay 5 if you have a 50-cent piece
99 cents
No, you can't make 25 cents out of 22 coins
To make 89 cents with 6 coins, you have to first realize that the "9" part of the cents is comprised of 5 cents and 4 pennies. Therefore, you have to have 4 pennies and 85 cents using 2 coins; impossible, since you would need 3 coins(if you had half-dollars) to make that amount: a half-dollar, quarter, and a dime. Basically, it's impossible with only coins worth 0.01, 0.05, 0.10, 0.25, and 0.50 of the currency(US$, I assume?)
There are 6 ways using normal U.S coins, but their is probally a different amount using foreign coins....... :-)
It is impossible to have 14 coins equal to 25 cents.
The answer is: one quarter, one dime, one nickle and two pennies. Five coins in all.