6 A 'quarter'and 5 'one cents'
One quarter, 1 dime and 2 pennies
6 1*50 cents 2*20 cents 1*5 cents 1*2 cents and 1*1 cent. For cents (in a Euro).
Two Dime or 10 cents 10 x 2 = 20
To determine how many 20 cent coins make up $165.40, you would first convert the amount to cents, which is 16,540 cents. Then, you would divide this total by 20 cents (the value of each coin) to find the number of coins. Therefore, 16,540 cents divided by 20 cents equals 827 coins. So, 827 twenty-cent coins make up $165.40.
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6 A 'quarter'and 5 'one cents'
One quarter, 1 dime and 2 pennies
6 1*50 cents 2*20 cents 1*5 cents 1*2 cents and 1*1 cent. For cents (in a Euro).
The least amount would be 3 coins (half-dollar, dime, nickel) The most would be 65, all pennies.
Two Dime or 10 cents 10 x 2 = 20
To determine how many 20 cent coins make up $165.40, you would first convert the amount to cents, which is 16,540 cents. Then, you would divide this total by 20 cents (the value of each coin) to find the number of coins. Therefore, 16,540 cents divided by 20 cents equals 827 coins. So, 827 twenty-cent coins make up $165.40.
99 cents
No, you can't make 25 cents out of 22 coins
To make 89 cents with 6 coins, you have to first realize that the "9" part of the cents is comprised of 5 cents and 4 pennies. Therefore, you have to have 4 pennies and 85 cents using 2 coins; impossible, since you would need 3 coins(if you had half-dollars) to make that amount: a half-dollar, quarter, and a dime. Basically, it's impossible with only coins worth 0.01, 0.05, 0.10, 0.25, and 0.50 of the currency(US$, I assume?)
There are 6 ways using normal U.S coins, but their is probally a different amount using foreign coins....... :-)
It is impossible to have 14 coins equal to 25 cents.