The two numbers are x2 - x and 8x - 4.
The least common multiple is the product of the numbers divided by their greatest common factor. For this example, I will assume that x is a positive integer > 1, since otherwise x2-x = 0, and the least common multiple would then be 0. So, the next step is to determine the greatest common factor. To do that, factor each of the numbers.
These numbers can be rewritten as x(x-1) and 4(2x-1).
The factors of x2 - x are x and x-1.
The factors of 8x - 4 are 2, 2, and 2x-1. Neither x nor x-1 evenly divide 2x-1.
However, either x or x-1 is even, which means one of them is divisible by 2. Since 2 is a factor of 8x-4, the greatest common factor is at least 2, but since we do not know the value of x, the greatest common factor might be 4. So, the least common multiple is either
(x2-x)(8x-4)/2 = (8x3-12x2-4x)/2 = 4x3-6x2-2x
or (x2-x)(8x-4)/4 = (8x3-12x2-4x)/4 = 2x3-3x2-x.
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-if3X-1=11,what is the value of X^2+X?
they are telling u that X=5, so plug in a 5 anywhere there is an X, so now is 52 x 2x5= 5x5=25 , so now is: 25x(2x5), 2x5=10, so now is 25x10=250 ,so the answer is : x2x (2x) = 52x(2x)=52x(2x5)=25x2x5=250
To factor the quadratic expression x^2 - 9x - 8, we need to find two numbers that multiply to -8 (the constant term) and add up to -9 (the coefficient of the x-term). The two numbers are -1 and 8. Therefore, we rewrite the middle term -9x as -x - 8x. Now, we can factor the expression as (x - 8)(x + 1).