I think this question needs rewording. Maybe like 2x-9x-8 (144 as in a normal maths question)? Or x2x-9x-8 (x144, like a magnifiyer strength). Another rewording option is 2(-9x-8). This equals -18x-16=288 (remember a minus times a minus is a plus) === ===
(x-1)(x-8) is a possible way (it gives x^2 -9x+8) , but you don't say in the question whether it is adds or subtracts inbetween the terms, so this may not be the answer that you require.
You don't. This expression does not have any factors.
If: y = x2-7x+8 and y = -x2+9x-6 Then: x2-7x+8 = -x2+9x-6 So: 2x2-16x+14 = 0 => x2-8x+7 = 0 Therefore: x = 1 and x = 7 By substitution: x =1, y = 2 and x = 7, y = 8 Points of intersection: (1, 2) and (7, 8)
y = x2 - 7x + 8 y = -x2 + 9x - 6 subtract the 2nd from the 1st equation 0 = 2x2 - 16x + 14 simplify 0 = x2 - 8x + 7 factor it, since 7 = (-1)(-7) and -1 - 7 = -8 0 = (x - 1)(x - 7) let each factor equal to zero x - 1 = 0 or x - 7 = 0 solve for x thus, x = 1 and x = 7. Chose one of the equation and substitute x with 1, and 7 to find the corresponding y-values. y = x2 - 7x + 8 y = (1)2 - 7(1) + 8 = 1 - 7 + 8 = 2; (1, 2) intersection point y = (7)2 - 7(7) + 8 = 49 - 49 + 8 = 8; (7, 8) intersection point
x2 - 9x + 20 = (x - 4)( x - 5)
You don't need to factor that; you can add them together, since they have the same variable.However, assuming you might mean 81x squared + 9x, you can take out the common factor, which is 9x.
x2 - 9x = -8 ∴ x2 - 9x + 8 = 0 ∴ (x - 1)(x - 8) = 0 You can then solve it as well: ∴ x ∈ {1, 8}
x2 - 9x + 8 = (x-1)(x-8)
x2-9x = x(x-9)
x2-9x+8=0 has two solutions:x = 8x = 1
(x-9)(x+9)
x2=9x-20 x2-9x+20=0 Factor: (x-4)(x-5)=0 x={4,5}
(x + 8)(x + 1)
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
x2 - 9x + 18 = (x - 3)(x - 6)
(x + 8)(x + 1)
(x - 9)(x2 + 9x + 81)
You don't. This expression does not have any factors.