To factor the quadratic expression x^2 - 9x - 8, we need to find two numbers that multiply to -8 (the constant term) and add up to -9 (the coefficient of the x-term). The two numbers are -1 and 8. Therefore, we rewrite the middle term -9x as -x - 8x. Now, we can factor the expression as (x - 8)(x + 1).
You don't. This expression does not have any factors.
If: y = x2-7x+8 and y = -x2+9x-6 Then: x2-7x+8 = -x2+9x-6 So: 2x2-16x+14 = 0 => x2-8x+7 = 0 Therefore: x = 1 and x = 7 By substitution: x =1, y = 2 and x = 7, y = 8 Points of intersection: (1, 2) and (7, 8)
y = x2 - 7x + 8 y = -x2 + 9x - 6 subtract the 2nd from the 1st equation 0 = 2x2 - 16x + 14 simplify 0 = x2 - 8x + 7 factor it, since 7 = (-1)(-7) and -1 - 7 = -8 0 = (x - 1)(x - 7) let each factor equal to zero x - 1 = 0 or x - 7 = 0 solve for x thus, x = 1 and x = 7. Chose one of the equation and substitute x with 1, and 7 to find the corresponding y-values. y = x2 - 7x + 8 y = (1)2 - 7(1) + 8 = 1 - 7 + 8 = 2; (1, 2) intersection point y = (7)2 - 7(7) + 8 = 49 - 49 + 8 = 8; (7, 8) intersection point
x2 - 9x + 20 = (x - 4)( x - 5)
You don't need to factor that; you can add them together, since they have the same variable.However, assuming you might mean 81x squared + 9x, you can take out the common factor, which is 9x.
x2 - 9x = -8 ∴ x2 - 9x + 8 = 0 ∴ (x - 1)(x - 8) = 0 You can then solve it as well: ∴ x ∈ {1, 8}
x2 - 9x + 8 = (x-1)(x-8)
x2-9x = x(x-9)
x2-9x+8=0 has two solutions:x = 8x = 1
(x-9)(x+9)
x2=9x-20 x2-9x+20=0 Factor: (x-4)(x-5)=0 x={4,5}
(x + 8)(x + 1)
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
x2 - 9x + 18 = (x - 3)(x - 6)
(x + 8)(x + 1)
(x - 9)(x2 + 9x + 81)
You don't. This expression does not have any factors.