-9x^2 - 15x
Supose A = 9x and B = 9y are the two numbers, where x and y are coprime and x < y. A*B = LCM*HCF So that 9x*9y = 126*9 so x*y = 14 so (x,y) = (1,14) or (2,7). Also, B - A = 45 or 9y - 9x = 45 so that y - x = 5 So (x,y) = (2,7) and the two numbers are 18 and 63.
You don't need to factor that; you can add them together, since they have the same variable.However, assuming you might mean 81x squared + 9x, you can take out the common factor, which is 9x.
Let the numerator be x, so the denominator is x + 4. So we have:x/(x + 4) = 9/15 (cross multiply)15x = 9(x + 4)15x = 9x + 3615x - 9x = 9x - 9x + 366x = 366x/6 = 36/6x = 6x + 4 = 6 + 4 = 10Sine the numerator is 6 and the denominator is 10, then the fraction is 6/10, which in the simplest form is equal to 3/5.Since 9/15 in the simplest form is also equal to 3/5, then 6/10 is equivalent to 9/15.Thus, 6/10 is the required fraction.
3X
18x2y
9x squared-15x squared = -6
18x2
9x + 7 = 15x + 1 ___-1_______-1 9x + 6 = 15x -9x_____-9x ____6=6x ____/6_/6 ____1=x x equals 1.
3x. 15x - 9x = 6x 9x - 6x = 3x 6x - 3x = 3x 3x - 3x = 0
9x is the lowest common multiple. (9x * 1 = 9x) (x * 9 = 9x)
-15x + 1
you just add 6x+9x to get 15x then minus 25 from 18 to get -7 thus the answer will be 15x-7
-9x^2 - 15x
15x^4-12x^2+9x/3x
it's an easy one :)-6 - 6x = 9 - 9x-6x + 9x = 9 + 63x = 15x = 15/3X = 5
6x + 9x^3 = 3x*(2 + 3x^2)