To find the least common multiple (LCM) of a set of numbers, we need to determine the prime factors of each number. The numbers given are 2, 3, 4, 5, 6, 9, and 10. The prime factors of these numbers are 2, 3, 2^2, 5, 2 * 3, 3^2, and 2 * 5 respectively. To find the LCM, we need to take the highest power of each prime factor that appears in any of the numbers. Multiplying these highest powers together gives us the LCM, which in this case is 2^2 * 3^2 * 5 = 180. Therefore, the least number divisible by 2, 3, 4, 5, 6, 9, and 10 is 180.
2
A number that is divisible by 2, 3, 4, 5, and 10 must be divisible by the least common multiple of these numbers, which is 60. Therefore, any number that is a multiple of 60 will be divisible by 2, 3, 4, 5, and 10. This is because 60 is the smallest number that contains all the prime factors of 2, 3, 4, 5, and 10.
To find the greatest number between 900 and 1000 that is divisible by 10, 5, and 2, we need to find the least common multiple (LCM) of 10, 5, and 2, which is 10. So, we look for the highest multiple of 10 between 900 and 1000, which is 990. To find the least number between 900 and 1000 that is divisible by 10, 5, and 2, we can simply find the smallest multiple of 10 in that range, which is 900.
There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
If its divisible by 5 AND 2 it must be divisible by 10 So you just have to pick the only number between 21 and 39 that's divisible by 10
1
180 is divisible by 2, 3, 4, 5, 9, and 10.
The smallest number that is divisible by 2, 6, and 10 is 30
2
A number that is divisible by 2, 3, 4, 5, and 10 must be divisible by the least common multiple of these numbers, which is 60. Therefore, any number that is a multiple of 60 will be divisible by 2, 3, 4, 5, and 10. This is because 60 is the smallest number that contains all the prime factors of 2, 3, 4, 5, and 10.
Any number that is divisible by 10 is an even number and hence divisible by 2 also. It can also be stated that because 10 is divisible by 2, all numbers divisble by 10 are also divisible by 2.
360
360
the least number divisible by 1, 2, 3, 4 & 6 is 12.
Because 10 is divisible by both 2 and 5
To find the greatest number between 900 and 1000 that is divisible by 10, 5, and 2, we need to find the least common multiple (LCM) of 10, 5, and 2, which is 10. So, we look for the highest multiple of 10 between 900 and 1000, which is 990. To find the least number between 900 and 1000 that is divisible by 10, 5, and 2, we can simply find the smallest multiple of 10 in that range, which is 900.
No all numbers ending in 0 (zero) are divisible by 10 and therfore divisible by at least 5 and 2. 1180 has the prime factors:2 * 2 * 5 * 59