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What is the least whole number greater than 100 with exactly 3 divisors?
Wiki User
∙ 15y ago
This question is easy and just takes logic. All numbers have at least 2 divisors, 1 and itself. So for a number to have 3 divisors, it must be a square number, with no other divisors. So this rules out even numbers. Square numbers above 100 are: 11 x 11 = 121 12 x 12 = 144 13 x 13 = 169 14 x 14 = 196 And so on. Already we can rule out 14 x 14 and 12 x 12 because they give us even results. So now lets look at 121 and 169. There is nothing below 11 that can divide evenly into 121 (except one) so therefore our answer is 121. 8) This question is easy and just takes logic. All numbers have at least 2 divisors, 1 and itself. So for a number to have 3 divisors, it must be a square number, with no other divisors. So this rules out even numbers. Square numbers above 100 are: 11 x 11 = 121 12 x 12 = 144 13 x 13 = 169 14 x 14 = 196 And so on. Already we can rule out 14 x 14 and 12 x 12 because they give us even results. So now lets look at 121 and 169. There is nothing below 11 that can divide evenly into 121 (except one) so therefore our answer is 121. 8)
Wiki User
∙ 15y ago
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