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What is the length in feet of the diagonal of a rectangle when one side is greater than the other side by 24 inches and has an area of 6912 square inches showing work?
Wiki User
∙ 10y ago
Convert the inches into feet which are 24/12 = 2 ft and 6912/144 = 48 sq ft
Let the sides be x+2 and x:-
As an equation: (x+2)*x = 48
As a quadratic equation: x2+2x-48 = 0
Factorising: (x-6)(+8) = 0
Solution: x = 6 or x = -8 so x = 6 because you can't have negative dimensions
Therefore: (6+2)*6 = 48 sq ft
Using Pythagoras' theorem: 82+62 = 100 and its square root is 10
Answer: diagonal is 10 feet long
Wiki User
∙ 10y ago
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