0
What else can I help you with?
What is the limit as x approaches 2 of 1x-22?
1(x)-22 x=2 1(2)-22=Limit Limit=2-22 Limit= -20
How do you integrate 2x over 2x-2?
Integral of 2x dx /(2x-2) Let 2x=u 2 dx = du dx = (1/2) du Integral of 2x dx /(2x-2) = Integral of (1/2) u du / (u-2) = Integral of 1/2 [ (u-2+2) / (u-2)] dx = Integral of 1/2 [ 1+ 2/(u-2)] dx = u/2 + (1/2) 2 ln(u-2) + C = u/2 + ln(u-2) + C = (2x/2) + ln(2x-2) + C = x + ln(2x-2) + C
How do you do 2x times 2x?
2x * 2x (2*2=4) therefore, 2x*2x equals 4x2.
What is negative 2 to the fifth power?
-2x-2x-2x-2x-2=-32
What is 3-2(2x-1)2x?
3+4x+2-2x=2x+5
What is the limit of 9x divided by 2x as x approaches 0?
9x/2x = 9/2 = 4.5
What is the limit of 1-cos x over x squared when x approaches 0?
1
How do you solve the limit as x approaches 90 degrees of cos 2x divided by tan 3x?
Take the limit of the top and the limit of the bottom. The limit as x approaches cos(2*90°) is cos(180°), which is -1. Now, take the limit as x approaches 90° of tan(3x). You might need a graph of tan(x) to see the limit. The limit as x approaches tan(3*90°) = the limit as x approaches tan(270°). This limit does not exist, so we'll need to take the limit from each side. The limit from the left is ∞, and the limit from the right is -∞. Putting the top and bottom limits back together results in the limit from the left as x approaches 90° of cos(2x)/tan(3x) being -1/∞, and the limit from the right being -1/-∞. -1 divided by a infinitely large number is 0, so the limit from the left is 0. -1 divided by an infinitely large negative number is also zero, so the limit from the right is also 0. Since the limits from the left and right match and are both 0, the limit as x approaches 90° of cos(2x)/tan(3x) is 0.
What is the limit of sin multiplied by x minus 1 over x squared plus 2 as x approaches infinity?
As X approaches infinity it approaches close as you like to 0. so, sin(-1/2)
What is the limit as x approaches 0 of 1 plus cos squared x over cos x?
2
Find limit x approaches 0.5 when 2x to power of 2 plus 5x-3 divide by 2x-1?
lim x->.5 of (2x2 +5x-3)/(2x-1) First factor 2x2 +5x-3 as (2x-1)(x+3) Now note that the (2x-1) cancels out so you have lim x->0.5 of x+3 and this is 3.5
What is the limit as x approaches 2 of 1x-22?
1(x)-22 x=2 1(2)-22=Limit Limit=2-22 Limit= -20
Why does 7x over 2 equal 2x plus x plus x over 2?
7x = 4x+2x+1xSo 7x/2 = 4x/2 + 2x/2 + x/2 (by the distributive property of division over addition) = 2x + x + x/2
What is the limit of x2 as x approaches 0?
Here, just plug x=0 into x^2 to get 0^2=0. The limit is 0.
What is the limit of sine squared x over x as x approaches zero?
So, we want the limit of (sin2(x))/x as x approaches 0. We can use L'Hopital's Rule: If you haven't learned derivatives yet, please send me a message and I will both provide you with a different way to solve this problem and teach you derivatives! Using L'Hopital's Rule yields: the limit of (sin2(x))/x as x approaches 0=the limit of (2sinxcosx)/1 as x approaches zero. Plugging in, we, get that the limit is 2sin(0)cos(0)/1=2(0)(1)=0. So the original limit in question is zero.
What is the limit of 2x divided by tanx plus sinx as it approaches zero from the right?
This answer will assume you understand basic concepts of limits. This is what I am interpreting your problem as: lim x->0+ [(2x)/(tan(x) + sin(x))] It is easy to see that simple substitution of 0 in for x will yield an indeterminate form 0/0. So, L'Hopital's rule will be applied to solve this limit. This rule states that an indeterminate form in a limit can still be solved for by deriving the top and bottom of the divided function and resolving for the limit. The "top" of this expression is 2x, and the "bottom" is tan(x) + sin(x). Deriving both top and bottom yields a new expression: 2/(sec2(x)+cos(x)) Substitution of 0 into this expression yields a determinate form, because sec2(0)=1/cos2(0)=1/1=1 and cos(0)=1, so the new "bottom" is 1+1=2. The general limit of this new expression is equal to the general limit of the original expression, so: lim x->0 [2/(sec2(x) + cos(x))] = 2/2 = 1 = lim x->0 [(2x)/(tan(x) + sin(x))] Since this is a general limit, the limit as x approaches zero from the left and right are equal, so they are both 1. The answer is 1.
What is the limit of x squared plus four x plus four all over x squared minus 4 as x approaches 2?
The "value" of the function at x = 2 is (x+2)/(x-2) so the answer is plus or minus infinity depending on whether x approaches 2 from >2 or <2, respectively.
