answersLogoWhite

0

Integral of 2x dx /(2x-2)

Let 2x=u

2 dx = du

dx = (1/2) du

Integral of 2x dx /(2x-2) = Integral of (1/2) u du / (u-2)

= Integral of 1/2 [ (u-2+2) / (u-2)] dx

= Integral of 1/2 [ 1+ 2/(u-2)] dx

= u/2 + (1/2) 2 ln(u-2) + C

= u/2 + ln(u-2) + C

= (2x/2) + ln(2x-2) + C

= x + ln(2x-2) + C

User Avatar

Wiki User

14y ago

Still curious? Ask our experts.

Chat with our AI personalities

MaxineMaxine
I respect you enough to keep it real.
Chat with Maxine
RossRoss
Every question is just a happy little opportunity.
Chat with Ross
ReneRene
Change my mind. I dare you.
Chat with Rene

Add your answer:

Earn +20 pts
Q: How do you integrate 2x over 2x-2?
Write your answer...
Submit
Still have questions?
magnify glass
imp