Integral of 2x dx /(2x-2)
Let 2x=u
2 dx = du
dx = (1/2) du
Integral of 2x dx /(2x-2) = Integral of (1/2) u du / (u-2)
= Integral of 1/2 [ (u-2+2) / (u-2)] dx
= Integral of 1/2 [ 1+ 2/(u-2)] dx
= u/2 + (1/2) 2 ln(u-2) + C
= u/2 + ln(u-2) + C
= (2x/2) + ln(2x-2) + C
= x + ln(2x-2) + C
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=2x2+x+4x+2=x(2x+1)+2(2x+1)=(2x+1)(x+2) by spaz licker enjoy slag ;)
2x2 - 13x - 7 = (2x + 1)(x - 7)
If you mean: 2x2+11x+15 then it is (2x+5)(x+3) when factored
2x2 + 7x + 6 = 2x2 + 4x + 3x + 6 = 2x(x + 2) + 3(x + 2) = (x + 2)(2x + 3)
2x2 + 5x = x*(2x + 5)