=2x2+x+4x+2=x(2x+1)+2(2x+1)=(2x+1)(x+2) by spaz licker enjoy slag ;)
2x2 - 13x - 7 = (2x + 1)(x - 7)
2x2 + 7x + 6 = 2x2 + 4x + 3x + 6 = 2x(x + 2) + 3(x + 2) = (x + 2)(2x + 3)
If you mean: 2x2+11x+15 then it is (2x+5)(x+3) when factored
2x2 + 5x = x*(2x + 5)
2x2- 2x = 2x*(x - 1)
(2x)2 times (2x)2 = 16x4 (2x2) times (2x2) = 4x4
2x2(2x - 1)(2x + 1)(4x2 + 1)
4x4 + 1 = (2x2 - 2x + 1)(2x2 + 2x + 1)
2x2 + 2x = 2x(x+1)
d/dx(1/2x) = -1/(2x2)
(x3 + 3x2 - 2x + 7)/(x + 1) = x2 + 2x - 4 + 11/(x + 1)(multiply x + 1 by x2, and subtract the product from the dividend)1. x2(x + 1) = x3 + x22. (x3 + 3x2 - 2x + 7) - (x3 + x2) = x3 + 3x2 - 2x + 7 - x3 - x2 = 2x2 - 2x + 7(multiply x + 1 by 2x, and subtract the product from 2x2 - 2x + 7)1. 2x(x + 1) = 2x2 + 2x2. (2x2 - 2x + 7) - (2x2 + 2x) = 2x2 - 2x + 7 - 2x2 - 2x = -4x + 7(multiply x + 1 by -4, and subtract the product from -4x + 7)1. -4(x + 1) = -4x - 42. -4x + 7 - (-4x - 4) = -4x + 7 + 4x + 4 = 11(remainder)
2x2 - 72 would be factored into (2x - 12)(x + 6) or (2x + 12)(x - 6) To double check, multiply each pair: (2x - 12)(x + 6) = 2x2 + 12x - 12x - 72 = 2x2 - 72 (2x + 12)(x - 6) = 2x2 - 12x + 12 x - 72 = 2x2 - 72
4x2+2x-20 2x2+x-10 2x2+5x-4x-10 x(2x+5)-2(2x+5) (x-2)(2x+5)
2x2 - 5x + 12 does not factor. 2x2 - 5x - 12 factors into (2x + 3)(x - 4) 2x2 + 5x - 12 factors into (2x - 3)(x + 4)
2x2 + 17x - 9 = 2x2 + 18x - x - 9 = 2x(x + 9) - 1(x + 9) = (2x - 1)(x + 9)
2x3 + 2x2 = 2x2 * (x + 1)