What is the logarithmic form of the equation e4x 2981?

Answer 1

Assuming your equation is: e^4x = 2981

Then taking the logs to base e (natural logs) of both sides gives:

ln(e^4x) = ln(2981)

→ 4x = ln(2981)

[Note: The 2981 looks like it has been rounded to a whole number from approx 2980.958 which means the value of x was a whole number (to which ln(2981) rounds).]