Best Answer

My interpretation of the wording is:

. . . .21e4x

y = ---------

. . . . . .x

From here, just take the derivative, using the quotient rule:

y' = 21* [4e3x * ex * x - 1 * e4x] / x2

= 21 * [e4x](4x - 1) / x2

When x=1

y = 21e4

At x=1, gradient = 63e4

Point gradient formula gives:

y - 21e4 = 63e4 * (x - 1)

y = 63e4x - 42e4

That should be the answer.

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Q: How to find the equation of the line tangent to the graph of y is equal to 21 times e with an exponent of 4x divided by x at the point x is equal to 1 and you need the slope and what y is equal to?
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