The density of lead is approximately 11.34 grams per cubic centimeter. To find the mass of 100 milliliters of lead, we first need to convert milliliters to cubic centimeters since they are equivalent. So, 100 milliliters is equal to 100 cubic centimeters. Using the density of lead, we can calculate the mass by multiplying the volume (100 cm³) by the density (11.34 g/cm³), resulting in a mass of 1134 grams.
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The mass of the lead will depend upon the density of the lead which depends upon the temperature of the lead.
Assuming near room temperature the density of lead is 11.34 g/ml.
density = mass / volume
→ mass = volume × density = 100 ml × 11.34 g/ml = 1134 g.
The answer depends on the temperature, but at room temperature (20 deg C), 100 ml of water would have a mass of 99.82 grams.
Does not convert; milligrams (mg) and grams are measures of weight or mass and mL (milliliters) is a measure of volume.
The conversion of milliliters to grams depends on the density of the substance in question. For water, which has a density of 1 gram per milliliter, 100 milliliters would be equal to 100 grams. However, for other substances with different densities, the conversion would vary. It is important to know the specific density of the substance to accurately convert milliliters to grams.
5 grams of salt in 75 grams of water = 5 grams of salt in 80 grams of the solution.So the mass concentration = 5/80 = 100*5/80% = 6.25%5 grams of salt in 75 grams of water = 5 grams of salt in 80 grams of the solution.So the mass concentration = 5/80 = 100*5/80% = 6.25%5 grams of salt in 75 grams of water = 5 grams of salt in 80 grams of the solution.So the mass concentration = 5/80 = 100*5/80% = 6.25%5 grams of salt in 75 grams of water = 5 grams of salt in 80 grams of the solution.So the mass concentration = 5/80 = 100*5/80% = 6.25%
1 ml of water has a mass of approx 1 gram so 50 ml = approx 50 grams. Suppose x grams of sugar are required for a 3% (by mass) solution. Therefore, x/(50+x) = 3/100 That is 97x = 150 so that x = 150/97 = 1.546 grams, approx.