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Q: What is the mass of 25 cm3 of pure water -?

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density = mass ÷ volume= 35g ÷ 25 cm3= 1.4 g/cm3 (= 1.4 gcm-3)Density = Mass/Volume = 35.0/25.0 = 1.4 g per cm3

Density = Mass/Volume so Volume = Mass/Density The density of lead is 11.3 grams per cm3 so volume = 282.5/11.3 = 25 cm3

25/29.4 = 0.85 grams/cm3

For fresh water at room temperature, it is 25 grams

The answer will depend the volume of the bottle and the temperature and pressure. Assuming that the experiment is carried out at normal temperature (20 deg C) and one atmospheric pressure, the density of water is 0.9982071 grams per cm3. So, if the volume of the water in the bottle is V cm3 = V cc or V ml, then the mass of the filled bottle is 25 + V*0.9982071 grams.

Related questions

25 g

1.25 g/cm3

Density = Mass/Volume = 16.0/25 = 0.64 grams per cm3

The volume cannot be 25 cm, since that is not a volume measure. Assuming the volume is 25 cm3, Density = mass/volume = 500 g / 25 cm3 = 20 grams per cm3

25 cm3

The first objects density is 2 g/cm3 and the second is 3 g/cm3. You just simple divide the mass by the volume to get the density.

25 g/cm3 x 60 cm3 = 1500 g

The object has a density of 0.32 g/cm3

The mass is 262 g.

The formula for density is mass divided by the volume. The density is 5.6 grams/25 cm3, which is equal to 0.224 g/cm3.

density = mass ÷ volume= 35g ÷ 25 cm3= 1.4 g/cm3 (= 1.4 gcm-3)Density = Mass/Volume = 35.0/25.0 = 1.4 g per cm3

Density = Mass/Volume = 25g / 4 cm3 = 6.25 g/cm3

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