Formula for sphere volume: 4/3πr³
Plug in 18 for r; the volume is 24429 cm³.
Density of iron: 7850 kg/m³
24429 cm³ • 7850 kg/m³ = 191.76765 kg
What is the mass of solid iron wrecking ball of radius 18 cm
Volume of ball = 4/3*pi*r^3 = 24229 cm^3Therefore mass = Volume*Density = 24229*7.87 = 192256 grams = 192.256 kg.
The answer is 6.6
The answer will depend on what the two given measures are. The total surface area is 2*pi*r*(r + h) where r is the radius and h the height.
0
450 square centimeters
An arbitrary large number is the answer for anyrectangle, up to that with a length of 9cm, and 0cm as the width will have a perimeter of 18cm.Similarly, any rectangle up to that with sides 0cm long, and a width of 9cm will have your 18cm perimeter.
190kg
54.7
radius = 18/2 = 9 cm
Using 3.14 as Pi the area of circle is: 1017.36
1,017.9 cm2
9 cm (r = d/2)
SA = 904.78 cm2
The perimeter is pi*r + 2r = 92.6 cm
A cone with a base radius of 12 cm and a height of 18 cm has a volume of 2,714.34 cm3
The diameter is always double the radius so in this case, it is 18cm
The answer is 6.6
Volume = pi*r2*h = 40715.04 cubic cm