What is the mass of solid iron wrecking ball with a radius of 18cm with solution?

Answer 1

What is the mass of solid iron wrecking ball of radius 18 cm

Answer 2

Formula for sphere volume: 4/3πr³

Plug in 18 for r; the volume is 24429 cm³.

Density of iron: 7850 kg/m³

24429 cm³ • 7850 kg/m³ = 191.76765 kg

Answer 3

To calculate the mass of the solid iron wrecking ball, we first need to determine its volume using the formula for the volume of a sphere: V = (4/3) * π * r^3, where r is the radius. Plugging in the radius of 18 cm, we get V = (4/3) * π * 18^3 = 24408π cm^3. Next, we calculate the mass using the density of iron, which is approximately 7.87 g/cm^3. Therefore, the mass of the solid iron wrecking ball would be 24408π * 7.87 ≈ 192,214.33 grams or 192.21 kg.

Answer 4

Well, let's imagine that solid iron wrecking ball for a moment. With a radius of 18cm, it sounds like a hefty piece of metal! To find its mass, we can use the formula for the volume of a sphere (4/3 * π * r^3) and then multiply it by the density of iron, which is around 7.87 g/cm³. This will give us the mass of the iron wrecking ball, a weighty reminder of the strength and resilience found in even the heaviest of objects.

Answer 5

Oh, dude, you're asking me to calculate the mass of a solid iron wrecking ball with a radius of 18cm? Like, are we building a wrecking ball or planning to swing it around for fun? Anyway, to answer your question, the mass of the wrecking ball can be calculated using the formula for the volume of a sphere and the density of iron. Just plug in the numbers and you'll have your answer.

Answer 6

Volume of ball = 4/3*pi*r^3 = 24229 cm^3Therefore mass = Volume*Density = 24229*7.87 = 192256 grams = 192.256 kg.