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The square's sides will be the sqrt 2 = about 1.414 inches.

(NOTE that this only happens when the circle is 2 inches in diameter. For a circle 3 inches in diameter, the diagonal measurement 3 = (sq rt 2) s and s = about 2.122 inches, not the square root of 3)

The largest square will have a DIAGONAL the same length as the DIAMETER of the circle. This is clear when you imagine that it is the largest dimension of any square. With the diagonal length being the hypotenuse of the two right triangles that form the square, the diagonal length equals the square root of the sum of the squares (of the two sides of the square)

diagonal = (sq rt 2) x side

diameter = sq rt (s^2 + s^2).

2 inches = sq rt (2 s^2)

2 inches - (sq rt 2) x s

2 inches = 1.414 s

and s = 1.414

Q: What is the maximum size square that will fit into a 2 inch circle?

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one that is 16in in diameter.

A square with sides of 0.4985 units will fit in the circle.

It depends on what you mean by a certain size circle. If the certain size is the diameter, then the answer is 54 inches. If the certain size is the radius, then the answer is 108 inches. If the certain size is the circumference, then the answer is 54 / 3.14159 or about 17.19 inches

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Related questions

one that is 16in in diameter.

-- Every circle has a diameter of some size. -- All of the diameters that you can draw in the same circle are the same size. -- The smaller the circle is, the smaller its diameter is. There's no minimum size. -- The larger the circle is, the larger its diameter is. There's no maximum size.

The answer depends on their relative size: is the circle inside the square, the square inside the circle or something else?

A square inch is one inch by one inch. like it is 1 inch tall and 1 inch long. An inch is just a measure of a line. so it is the same size. it is just a square.

Area of a circle = pi*radius2 The radius of the circle will be 1/2 the size of the length of a side of the square.

A square with sides of 0.4985 units will fit in the circle.

1 inch square

16x16 inch tiles are square. If you place them on a circle, the edges will hang off, so we first need to find the size of the largest square that will fit in the circle. The largest square can be made of four isosceles triangles whose equal sides are equal to the length of the radius, so the area of the contained square is 2r2. An 11-foot diameter circle has a radius of 5.5 feet, so the square has an area of 2(5.5)2 = 60.5 square feet, or 60.5 * 122 square inches = 8712 square inches. The 16x16 tiles are 256 square inches, so 8712 / 256 = 34.03125 tiles that fit completely in the circle.

The answer requires information on the size of the circle: its radius, diameter or circumference.

Pi is a constant. It doesn't depend on the size of the circle. Pi is approximately 3.1416.

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A square of any size would be similar.