A square with sides of 0.4985 units will fit in the circle.
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one that is 16in in diameter.
it would be the diameter of the smaller circle times sqrt 2
It depends on what you mean by a certain size circle. If the certain size is the diameter, then the answer is 54 inches. If the certain size is the radius, then the answer is 108 inches. If the certain size is the circumference, then the answer is 54 / 3.14159 or about 17.19 inches
When the diameter of a circle is halved, the radius is also halved since the radius is half of the diameter. The area of a circle is calculated using the formula A = πr^2, where r is the radius. If the radius is halved, the area is reduced to one-fourth of its original size because the radius is squared in the formula. Therefore, halving the diameter of a circle results in the area being reduced to one-fourth of its original area.
The square's sides will be the sqrt 2 = about 1.414 inches.(NOTE that this only happens when the circle is 2 inches in diameter. For a circle 3 inches in diameter, the diagonal measurement 3 = (sq rt 2) s and s = about 2.122 inches, not the square root of 3)The largest square will have a DIAGONAL the same length as the DIAMETER of the circle. This is clear when you imagine that it is the largest dimension of any square. With the diagonal length being the hypotenuse of the two right triangles that form the square, the diagonal length equals the square root of the sum of the squares (of the two sides of the square)diagonal = (sq rt 2) x sidediameter = sq rt (s^2 + s^2).2 inches = sq rt (2 s^2)2 inches - (sq rt 2) x s2 inches = 1.414 sand s = 1.414