The mean (or average) of 8, 9, and 10 is 9.
-9,-11,-8,-12,-10
15
8, 9, 11 and 12
8 and 9/10 = 89/10
9;9;9 Mean = sum of scores / number of scores = 9+9+9 / 3 = 27 / 3 = 9 another example is 7, 9, 11 8, 9, 10 etc even: 7, 8, 12
If you mean: -9-10+8 then their sum is -11
MEAN = ( 8+10 )/2 = 18/2 =9
To find the mean, add all the numbers together: 5 + 7 + 9 + 9 + 9 + 10 + 10 + 5 = 64. Then, divide the sum by the total number of values, which is 8. So, the mean is 64 ÷ 8 = 8.
To find the mean, add all the numbers together and then divide by the count of the numbers. For the dataset 9, 9, 7, 9, 6, 7, 9, 8, 8, 8, the sum is 80. There are 10 numbers, so the mean is 80 divided by 10, which equals 8.
8.
If you mean: 8 9 10 11 and 12 then the average mean is 10
The mean is 9.6. The median is 8.5. The mode is 8. The range is 14.Rewrite the values from least to greatest:6, 7, 8, 8, 8, 9, 9, 10, 11, 20Mean is the average:(6 + 7 + 8 + 8 + 8 + 9 + 9 + 10 + 11 + 20)/10 = 96/10 = 9/6Median is the middle value:the mean of5th and 6thnumber= (8 + 9)/2 = 17/2 = 8.5Mode is thenumber that is repeated often:8 is repeated thrice so 8 is the mode.Range is the difference of the greatest value and the least value = 20 - 6 = 14
8mean = (9+3+8+10+12+6)/6= 48/6= 8
If you mean: 7/10, 7/9 and 7/8 then it is 7/8, 7/9 and 7/10 from greatest to least
14, 6, 8, 10, 9, 5, 7, 13 First re-arrange the terms into Rank Order. Hence 5,6,7,8,9,10,13,14. The MEDIAN is the Absolute middle term , which is (9+10) / 2 = 9.5 The MODE is is the most frequent term. As a;; terms occur with the same frequency of one. , then the Median is used as the Mode, Hence 9.5 again. THe MEAN is the sum of all the terms divided by the number of terms. Hence [5+6+7+8+9+10+13+14] / 8 => [72]/8 = 9 The means NB For good measure, the RANGE is 14 - 5 = 9 [
The mean of these, or any group of ten numbers, is 1/10th of their sum.
median = 8 mean = 7 mean < median.