The mean of 8, 9, 11, and 16 is 8+9+11+16 = 44 and 44/4 = 11 which is the mean average
the mean is the average; (9 +8+4 + X)/4 = 8; solve for X ; (21 +X)/4 = 8; X = 11
To find the mean average, add all the values together and divide by the number of values: → mean = (4 + 8 + 9 + 8 + 6 + 5 + 7 + 5 + 8) ÷ 9 = 60 ÷ 9 = 6 and 2/3 ≈ 6.67
The mean average is (9 + 15 + 4 + 8) ÷ 4 = 9; The median average is (8 + 9) ÷ 2 = 8.5 The mode average doesn't exist as each number appears once.
Since you left a space between the 8 and 9, and between the 3 and 4, I'm assuming you mean 8/9 divided by 3/4. To divide fractions you simply invert the divisor (3/4 to 4/3) and then multiply by the dividend (8/9). So 8/9 divided by 3/4 would be: 8/9 x 4/3 = 24/27 To reduce to its lowest form, it would be 8/9.
The mean of 8, 9, 11, and 16 is 8+9+11+16 = 44 and 44/4 = 11 which is the mean average
the mean is the average; (9 +8+4 + X)/4 = 8; solve for X ; (21 +X)/4 = 8; X = 11
If you mean: 8 over (9*4) then it is 2/9 in its simplest form
Mean: 5.5 Median: 7 Mode: 9, 0, 8
To find the mean average, add all the values together and divide by the number of values: → mean = (4 + 8 + 9 + 8 + 6 + 5 + 7 + 5 + 8) ÷ 9 = 60 ÷ 9 = 6 and 2/3 ≈ 6.67
If you mean: 4/1 times 9/8 then it is 36/8 = 9/2 or 4.5
4+9+7+6+8+8 equals 42.42 divided by 6 equals 7.
It is (9 + 9 + 7 + 7)/4 = 8
The mean average is (9 + 15 + 4 + 8) ÷ 4 = 9; The median average is (8 + 9) ÷ 2 = 8.5 The mode average doesn't exist as each number appears once.
median = 8 mean = 7 mean < median.
5 and 1/3
6