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When the lower 50 percent of data has greater range the mean will be what to the median?
Wiki User
∙ 11y ago
Whatever you like. The median value for each of the following three sets is 10.
For the set {1, 9, 11, 12}. the mean is 8.25, smaller than the median.
For the set {1, 9, 15, 15}. the mean is 10, the same as the median.
For the set {1, 9, 15, 16}. the mean is 10.25, larger than the median.
Wiki User
∙ 11y ago
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How does subtracting the same amount from each value in a data set affect the mean median mode and range?
The mean, the median, the mode and the upper and lower limits of the range would each be reduced by the amount subtracted.
How do you find the range when your median is 20?
There is no direct relationship between the range and the median. So knowing that your median is 20 does not automatically give you the range. The median is just the middle value. That does not tell you what the first and last values are, which is what you need to know to find the range. The median of 19, 20 and 21 is 20, and the range is 2. The median of 4, 20 and 79 is also 20, but the range is 75. The median of 8, 16, 17, 23, 50 and 320 is also 20, but the range is 312. So, as you can see, the Median in no way can tell you what the range will be. You need to know what all of the numbers are, or at least the lowest and highest to know the range.
Can numerical data have a range median or mode?
Yes. They must have a range and median. They may or may not have a mode.
What is the range median and mode in 80 and 80 and 100?
The range is 20, the median is 80, and the mode is 80.
What is the minimum number of guesses needed to find a specific number if you are given the hint higher or lower for each guess you make?
Assuming that you want to discount luck (if not, the answer would be 1), and that the guesser always guesses the median of the remaining range, the answer would be the (ceiling of the log(base 2) of the count of numbers in the range). If the log(base 2) is an exact integer, add 1. Example 1, pick a number between 1 and 9. There are 9 numbers in the range, so the log(base2) of 9 is ~3.16. The ceiling of that is 4. Do not add 1 for a final answer of 4. The full range is 1,2,3,4,5,6,7,8,9. The median is 5 First guess is 5. Higher - 6,7,8,9 is remaining range. 7 and 8 are the median numbers Second Guess is 8. Lower - 6,7 is the remaining range. 6 and 7 are the median numbers. Third guess is 7. Lower - 6 is the remaining range. 6 is the median number Fourth guess is 6. Correct. Example 2, pick a number between 1 and 16. There are 16 numbers in the range, so the log(base 2) of 16 is 4. The ceiling of 4 is 4. Add the 1 because the Log(base 2) is an integer, for a final answer of 5. Full range is 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16. The median numbers are 8 and 9. First Guess is 9. Lower - 1,2,3,4,5,6,7,8 is the remaining range. 4 and 5 are the median numbers Second Guess is 4. Higher - 5,6,7,8 is the remaining range. 6 and 7 are the median numbers. Third Guess is 6. Higher - 7,8 is the remaining range. 7 and 8 are the median numbers. Fourth Guess is 7. Higher - 8 is the remaining range. 8 is the median. Fifth guess is 8. Correct Both of these examples show worst case scenarios. A "lucky guess" will reduce the number of guess needed, possibly all the way to 1. Note: I do realize that to a math purist, in the examples where I said that the median numbers were x and y, the correct answer is that the median number is between x and y. Since I can not guess the number between the two numbers, I am bending the definition of median to treat the two bordering numbers as the median when the strict definition would list the median as being between those two numbers.
How does subtracting the same amount from each value in a data set affect the mean median mode and range?
The mean, the median, the mode and the upper and lower limits of the range would each be reduced by the amount subtracted.
Median mode range for 58?
Median = 58 Mode = 58 Range = 0
How do you find the range when your median is 20?
There is no direct relationship between the range and the median. So knowing that your median is 20 does not automatically give you the range. The median is just the middle value. That does not tell you what the first and last values are, which is what you need to know to find the range. The median of 19, 20 and 21 is 20, and the range is 2. The median of 4, 20 and 79 is also 20, but the range is 75. The median of 8, 16, 17, 23, 50 and 320 is also 20, but the range is 312. So, as you can see, the Median in no way can tell you what the range will be. You need to know what all of the numbers are, or at least the lowest and highest to know the range.
What is the median and range for the numbers 3 30 62 and 40?
range - 59 median- 35
What does median mode and range?
Median means average, and range is the range of numbers in a group. For example, the range is from 52 to 71. I don't know what a mode is.
What are the mean median range and mode of 5436?
median= 4&3 range=3 mode= no mode
Can numerical data have a range median or mode?
Yes. They must have a range and median. They may or may not have a mode.
What is the range median and mode in 80 and 80 and 100?
The range is 20, the median is 80, and the mode is 80.
What is the median and the range?
math
Can the range be zero?
can the median be less than the range
What three numbers have a mean greater than 135 and the median number is not in the central group and a range less than 20?
If there are only three numbers, the median MUST be the central number. Any question that claims otherwise is incorrect.
What is the minimum number of guesses needed to find a specific number if you are given the hint higher or lower for each guess you make?
Assuming that you want to discount luck (if not, the answer would be 1), and that the guesser always guesses the median of the remaining range, the answer would be the (ceiling of the log(base 2) of the count of numbers in the range). If the log(base 2) is an exact integer, add 1. Example 1, pick a number between 1 and 9. There are 9 numbers in the range, so the log(base2) of 9 is ~3.16. The ceiling of that is 4. Do not add 1 for a final answer of 4. The full range is 1,2,3,4,5,6,7,8,9. The median is 5 First guess is 5. Higher - 6,7,8,9 is remaining range. 7 and 8 are the median numbers Second Guess is 8. Lower - 6,7 is the remaining range. 6 and 7 are the median numbers. Third guess is 7. Lower - 6 is the remaining range. 6 is the median number Fourth guess is 6. Correct. Example 2, pick a number between 1 and 16. There are 16 numbers in the range, so the log(base 2) of 16 is 4. The ceiling of 4 is 4. Add the 1 because the Log(base 2) is an integer, for a final answer of 5. Full range is 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16. The median numbers are 8 and 9. First Guess is 9. Lower - 1,2,3,4,5,6,7,8 is the remaining range. 4 and 5 are the median numbers Second Guess is 4. Higher - 5,6,7,8 is the remaining range. 6 and 7 are the median numbers. Third Guess is 6. Higher - 7,8 is the remaining range. 7 and 8 are the median numbers. Fourth Guess is 7. Higher - 8 is the remaining range. 8 is the median. Fifth guess is 8. Correct Both of these examples show worst case scenarios. A "lucky guess" will reduce the number of guess needed, possibly all the way to 1. Note: I do realize that to a math purist, in the examples where I said that the median numbers were x and y, the correct answer is that the median number is between x and y. Since I can not guess the number between the two numbers, I am bending the definition of median to treat the two bordering numbers as the median when the strict definition would list the median as being between those two numbers.
