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One of the base angle is 58 deg so the other base angle is 58 deg. Sum of all three angles is 180 deg so the third angle (the vertex angle) is 180 - 58 - 58 = 64 degrees.

Q: What is the measure of the vertex angle of an isosceles triangle if one of its base angles measures 58?

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40 degrees each

The sum of all three interior angles of any triangle, isosceles or not, is 180 degrees.

The base angles of an isosceles triangle are the two angles with the same measure, each formed by the intersection between the base of the triangle and one of the two legs.

isosceles triangle

100 degree, 40 degree and 40 degree.

Related questions

63

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(180 - 38)/2 = 71 degrees (base angles of an isosceles triangle are congruent).

If a triangle is an isosceles triangle as well as being a right-angled triangle, the size of the two angles (that are not right angles) are 45 degrees.

You are an isosceles triangle.

It is an isosceles triangle

In all triangles, the angles always measure up 180 degrees. In an isosceles triangle two of the angles are equal.

The vertex angle of an isosceles triangle is equal to the measure of each of its base angles. Therefore, if one of the base angles measures 42 degrees, then the vertex angle also measures 42 degrees.

40 degrees each

63 degrees

It is possible if neither of the angles in the triangle measures to 60 degrees