The largest number is 40. The smallest number is 30. 40-30=10.
25
If there are two numbers in the middle you find the middle in between that like if you hade 40 and 50 in the midlle the median would be 45.
When there is an even number of items in the data set the median is the mean average of the middle two. The middle two are the two items themselves, namely 20 and 40, so the median is (20 + 40)/2 = 30.
Mean: 33.75 Median: 34 Mode: 28
20, 40, 50
10, 10, 20, 30, 30, 50.
Median is the middle number. In case there are two middle numbers, you can either calculate the average for the result or mark both numbers.20 30 40 50 median is 35 or {30;40}
The median (middle) of these numbers is 36.
Let's say that this numbers are placed in order as x, y, z. So the median is y = 40, and the range is the difference between z and x. So z - x = 30. The sum is: x + y + z = 110 Substitute 40 for y, and x + 30 for z; x + 40 + (x + 30) = 110 2x + 70 = 110 subtract 70 to both sides. 2x = 40 divide by 2 to both sides; x = 20 so, z = x + 30 z = 20 + 30 = 50 Thus these numbers are 20, 40, and 50.
It is 27.5, the number halfway between the two middle numbers.
The answer can be shown by adding the two middle numbers (30 and 40), and dividing by 2. The answer is 35. :)
It is 30, the number halfway between the two middle numbers.
The median of the 12 primes less than 40 is 15.
It is 40, the middle number when they are in order.
The largest number is 40. The smallest number is 30. 40-30=10.
25