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Q: Set of three numbers is 110. The median of the numbers is 40 and the range is 30. What are the numbers?

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There are an even number of numbers so you have to take the middle two and get the average of them. The middle 2 numbers are 108 and 110. Add them together and divide by 2 and you get 109.

Let's say that this numbers are placed in order as x, y, z. So the median is y = 40, and the range is the difference between z and x. So z - x = 30. The sum is: x + y + z = 110 Substitute 40 for y, and x + 30 for z; x + 40 + (x + 30) = 110 2x + 70 = 110 subtract 70 to both sides. 2x = 40 divide by 2 to both sides; x = 20 so, z = x + 30 z = 20 + 30 = 50 Thus these numbers are 20, 40, and 50.

The numbers are 110, 111 and 112.

The prime factors of 110 are 2, 5 and 11. None of them have three digits.

100, as it is the middle value of the numbers.

The only prime number in that range is 113.

113 is the only prime number in that range.

112

You can multiply 2 times 11 times 5 to make 110! (2x11=22x5=110)

10

If this is the only information you have, the answer would be somewhere around 125. Usually, you would find the third quartile by first finding the median. Then find the median of all of the numbers between the median and the largest number, which is the third quartile.

The LCD of the given three numbers is 110

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