56, 57, 64, 65, 66, 75, 76 Mean: 65 and 4/7 Median: 65 Mode: There is no mode. Range: 20
Median of the set = arithmetic mean of 75 and 85 = 80
70.5 The median is the middle value, so I'll have to rewrite the list in order: 53 54 59 62 64 65 66 68 70 71 75 78 83 83 86 90 91 94 There are 18 numbers in the list, so there is no "middle" number. So, you take the average of the middle two numbers, which is 70 and 71. So the median is 70.5.
71 is the median of those numbers.
50, 51, 52, 54, 55, 56, 57, 59, 60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76
56, 57, 64, 65, 66, 75, 76 Mean: 65 and 4/7 Median: 65 Mode: There is no mode. Range: 20
mean = (65 + 56 + 57 + 75 + 76 + 66 + 64)/7 = 65.57 median = "middle" number = 65 mode = most common number = all are equally common
66
The median is 82.
Since the set of data is arranged in numerical order, first we need to find the median (also called the second quartile), which separates the data into two equal groups, in our case there are 6 numbers in each group.54 65 66 68 73 75 | 75 78 82 82 87 97The first quartile (also called the lower quartile) is the middle value of numbers that are below the median, in our case is 67.54 65 66 | 68 73 75 | 75 78 82 82 87 97The third quartile (also called the upper quartile) is the middle value of numbers that are above the median, in our case is 82.54 65 66 | 68 73 75 | 75 78 82 | 82 87 97The interquartile range is the difference between the first and third quartiles, which is 15, (82 - 67).
62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77 and 78.
Median of the set = arithmetic mean of 75 and 85 = 80
65
It is: 3
62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77 and 78.
60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78
60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78, 80.