Rearrange the terms into their rank order.
Already done!!! 63,65,66,75
For an EVEN number of terms; there are four terms here, and four is an even number.
You take the middle two terms, which are ,65, & 66. and find the mid-point between them, Which is 65.5
Hence ' 65.5 ' is the MEDIAN term.
NB If you have an ODD number of terms, 5 in this case, e,g, 63,65,66,66,75. Then you select the absolute middle term, which is ' 66 '.
Median of the set = arithmetic mean of 75 and 85 = 80
65,56,57,75,76 ,68,64. First of all rearrange the terms in RANK order. Hence 56,57,64,65,66,75,76. MEDIAN. Select the absolute middle term from the rank order, which is 65. 65 is the Median. NB There are three terms to either side of this number. MODE. Select the term that occurs most frequently. Since all the terms occur only once, then you select the middle term, which is 65 again. MEAN. You add all the terms and then divide by the number of terms. Hence [56+57+64+65+66+75+76] / 7 => 459/7 => 65.57142857... ~ 65.57 ( 2 d.p.) ( The Mean) RANGE . is the difference between the highest value and the lowest value. Hence 76 - 56 = 20 ( The range)
70.5 The median is the middle value, so I'll have to rewrite the list in order: 53 54 59 62 64 65 66 68 70 71 75 78 83 83 86 90 91 94 There are 18 numbers in the list, so there is no "middle" number. So, you take the average of the middle two numbers, which is 70 and 71. So the median is 70.5.
71 is the median of those numbers.
50, 51, 52, 54, 55, 56, 57, 59, 60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76
mean = (65 + 56 + 57 + 75 + 76 + 66 + 64)/7 = 65.57 median = "middle" number = 65 mode = most common number = all are equally common
66
65,56,57,75,76 ,68,64. First of all rearrange the terms in RANK order. Hence 56,57,64,65,66,75,76. MEDIAN. Select the absolute middle term from the rank order, which is 65. 65 is the Median. NB There are three terms to either side of this number. MODE. Select the term that occurs most frequently. Since all the terms occur only once, then you select the middle term, which is 65 again. MEAN. You add all the terms and then divide by the number of terms. Hence [56+57+64+65+66+75+76] / 7 => 459/7 => 65.57142857... ~ 65.57 ( 2 d.p.) ( The Mean) RANGE . is the difference between the highest value and the lowest value. Hence 76 - 56 = 20 ( The range)
The median is 82.
Since the set of data is arranged in numerical order, first we need to find the median (also called the second quartile), which separates the data into two equal groups, in our case there are 6 numbers in each group.54 65 66 68 73 75 | 75 78 82 82 87 97The first quartile (also called the lower quartile) is the middle value of numbers that are below the median, in our case is 67.54 65 66 | 68 73 75 | 75 78 82 82 87 97The third quartile (also called the upper quartile) is the middle value of numbers that are above the median, in our case is 82.54 65 66 | 68 73 75 | 75 78 82 | 82 87 97The interquartile range is the difference between the first and third quartiles, which is 15, (82 - 67).
62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77 and 78.
Median of the set = arithmetic mean of 75 and 85 = 80
65
62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77 and 78.
It is: 3
60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78
60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78, 80.