mean = (65 + 56 + 57 + 75 + 76 + 66 + 64)/7 = 65.57
median = "middle" number = 65
mode = most common number = all are equally common
The range of a data set is the difference between the largest and smallest number in your set of data. Median is the number that comes in the middle. 54, 55, 56 has a range of 54-56 and a median of 55. The set 53, 55, 57 has a median of 55 also!
56
7 Or -8
8
56' x 56' = 56 x 56 = 3136 sq feet.56' x 56' = 56 x 56 = 3136 sq feet.56' x 56' = 56 x 56 = 3136 sq feet.56' x 56' = 56 x 56 = 3136 sq feet.
Mean = 61.857142... Median = 57 Mode = 56 Range = 27
Mean: 60 Median: 56.5 Mode: 56 Range: 28
mean: 60 median: 56.5 mode: 56 range: [48,75]
Mean: 67.143 Median: 78 Mode: 56, 78, 85, 92, 65, 79, 15 Range: 77
65,56,57,75,76 ,68,64. First of all rearrange the terms in RANK order. Hence 56,57,64,65,66,75,76. MEDIAN. Select the absolute middle term from the rank order, which is 65. 65 is the Median. NB There are three terms to either side of this number. MODE. Select the term that occurs most frequently. Since all the terms occur only once, then you select the middle term, which is 65 again. MEAN. You add all the terms and then divide by the number of terms. Hence [56+57+64+65+66+75+76] / 7 => 459/7 => 65.57142857... ~ 65.57 ( 2 d.p.) ( The Mean) RANGE . is the difference between the highest value and the lowest value. Hence 76 - 56 = 20 ( The range)
For the set (87 81 75 75 75 70 62 62 62 62 62 56 56): The mean is 68.076923 repeating The median is 62 The mode is 62
The mean is calculated by adding all the numbers together and dividing by the total count. In this case, the mean would be (52+53+54+55+55+56+57+57+57+59+60) / 11 = 56.09. The median is the middle number when the values are arranged in numerical order, which in this case is 56. The mode is the number that appears most frequently, which is 57 in this dataset.
The median of two numbers is also their mean = (78+56)/2 = 67
The range of a data set is the difference between the largest and smallest number in your set of data. Median is the number that comes in the middle. 54, 55, 56 has a range of 54-56 and a median of 55. The set 53, 55, 57 has a median of 55 also!
MEAN [x(1) + x(2) + x(3) + x(4) + x(5) + x(6] / 6 = 9 Hence [x(1) + x(2) + x(3) + x(4) + x(5) + x(6] = 54 RANGE ; x(6) - x(1) = 4 x(6) = 4 + x(1) MEDIAN ; (x(3)+ x(4)) / 2 = 9 Hence x(3) + x(4) = 18 Substitute [x(1) + x(2) + 18 + x(5) + x(1) + 4 ] = 54 2x(1) + x(2) + x(5) = 32 Assume x(2) = x(5) for Mode. Then by substitution 2x(1) + 2x(2) = 32 2(x)1) + x(2)+ = 32 x(1) + x(2) = 16 So x)1) + x(2) = 6 + 10 (max. range) 7+9 or 8+8 Hence x(1) = 7 x(2) = 9 x(3) = 9 x(4) = 9 x(5) = 10 x(6) = 10
The median is the number in the middle. When you have a even number of numbers, as we do here, we take the mean of the two middle numbers. First put the numbers in ascending order. We have 20 37 49 56 . Since 37 and 49 are the two in the middle we take their mean. 37+49=86 and half of that is 43 so this is the median.
To find the mean, add up the numbers in the set and divide that total by 22 (the number of numbers there are) In a set with an even number of numbers, the median is the average of the middle two which appears to be 69.25 Since no number appears more often than any other, this set has no mode.