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mean = (65 + 56 + 57 + 75 + 76 + 66 + 64)/7 = 65.57

median = "middle" number = 65

mode = most common number = all are equally common

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What is the mean median mode and range of 72 56 69 75 48 56 57?

Mean = 61.857142... Median = 57 Mode = 56 Range = 27


What is the mean median mode and range 72 56 47 69 75 48 56 57?

Mean: 60 Median: 56.5 Mode: 56 Range: 28


What is the mean median mode and range of 72 56 47 69 75 48 56 57?

mean: 60 median: 56.5 mode: 56 range: [48,75]


What would you choose mean median mode or range for the numbers 56 78 85 92 65 79 15?

Mean: 67.143 Median: 78 Mode: 56, 78, 85, 92, 65, 79, 15 Range: 77


What is the mean median mode and range of 65 56 57 75 76 66 64?

65,56,57,75,76 ,68,64. First of all rearrange the terms in RANK order. Hence 56,57,64,65,66,75,76. MEDIAN. Select the absolute middle term from the rank order, which is 65. 65 is the Median. NB There are three terms to either side of this number. MODE. Select the term that occurs most frequently. Since all the terms occur only once, then you select the middle term, which is 65 again. MEAN. You add all the terms and then divide by the number of terms. Hence [56+57+64+65+66+75+76] / 7 => 459/7 => 65.57142857... ~ 65.57 ( 2 d.p.) ( The Mean) RANGE . is the difference between the highest value and the lowest value. Hence 76 - 56 = 20 ( The range)


What are the mean median and mode for 87 81 75 75 75 70 62 62 62 62 62 56 56?

For the set (87 81 75 75 75 70 62 62 62 62 62 56 56): The mean is 68.076923 repeating The median is 62 The mode is 62


What is the mean median and mode of 52 53 54 55 55 56 57 57 57 59 60?

The mean is calculated by adding all the numbers together and dividing by the total count. In this case, the mean would be (52+53+54+55+55+56+57+57+57+59+60) / 11 = 56.09. The median is the middle number when the values are arranged in numerical order, which in this case is 56. The mode is the number that appears most frequently, which is 57 in this dataset.


What is the median out of 78 and 56?

The median of two numbers is also their mean = (78+56)/2 = 67


How is it possible for two sets of data to consist of different numbers but have the same mean the same median the same mode?

The range of a data set is the difference between the largest and smallest number in your set of data. Median is the number that comes in the middle. 54, 55, 56 has a range of 54-56 and a median of 55. The set 53, 55, 57 has a median of 55 also!


What 6 numbers have a range 4 mean 9 median 9 mode 7 and add to 56?

MEAN [x(1) + x(2) + x(3) + x(4) + x(5) + x(6] / 6 = 9 Hence [x(1) + x(2) + x(3) + x(4) + x(5) + x(6] = 54 RANGE ; x(6) - x(1) = 4 x(6) = 4 + x(1) MEDIAN ; (x(3)+ x(4)) / 2 = 9 Hence x(3) + x(4) = 18 Substitute [x(1) + x(2) + 18 + x(5) + x(1) + 4 ] = 54 2x(1) + x(2) + x(5) = 32 Assume x(2) = x(5) for Mode. Then by substitution 2x(1) + 2x(2) = 32 2(x)1) + x(2)+ = 32 x(1) + x(2) = 16 So x)1) + x(2) = 6 + 10 (max. range) 7+9 or 8+8 Hence x(1) = 7 x(2) = 9 x(3) = 9 x(4) = 9 x(5) = 10 x(6) = 10


Find the median 37 56 49 and 20?

The median is the number in the middle. When you have a even number of numbers, as we do here, we take the mean of the two middle numbers. First put the numbers in ascending order. We have 20 37 49 56 . Since 37 and 49 are the two in the middle we take their mean. 37+49=86 and half of that is 43 so this is the median.


What is the mean median and mode of 56 58 59 60 63 64 65 66 67 68 69 69.5 70 70.5 71 71.5 72 73 74 75 76 77?

To find the mean, add up the numbers in the set and divide that total by 22 (the number of numbers there are) In a set with an even number of numbers, the median is the average of the middle two which appears to be 69.25 Since no number appears more often than any other, this set has no mode.