The median is the middle number of a set of numbers when they are arranged in order. If there is an odd amount of numbers, you take the middle number. If there are an even amount of numbers, as in this case, you take the number halfway between the two middle numbers. The two middle numbers are 75 and 80, so halfway between that is 77.5 which is the median.
Median of the set = arithmetic mean of 75 and 85 = 80
It is 85, the middle value, between 80 and 90.
median is 79. Write in order; median is middle number: {72, 89, 67, 81, 75, 79, 81, 80, 62, 64, 83} → {62, 64, 67, 72, 75, 79, 80, 81, 81, 83, 89} To find middle number, count the number of data items, add 1 and divide by 2. If this is a whole number, that is the data item which is the median; if it is a fraction, take the mean average of the data items of the positions either side of the fraction (eg if the fraction is 3.5, take the mean average of the 3rd and 4th data items) There are 11 data items → median is (11+1)/2 = 6th data item → median is 79
75
Sort the numbers into numerical order:54, 68, 70, 72, 75, 76, 76, 76, 80, 88, 88, 88, 88, 92, 92, 93The median is the middle number which as there are 16 numbers is the mean of the middle two (highlighted above):median = (76 + 80) ÷ 2 = 78.
74 74 75 77 80The median is 75.
To answer this question, first rearrange the data values in non-decreasing order, which results in 73 74 75 76 78 78 80. The median is defined as the value in the middle of such an array, in this instance 76.
80
The median is 82.
After putting them in order, cross out the 'ends' First 58 and 80 Then 58 and 74 You are left with 63 and 69 The median number is 66. The median is the number in the 'middle.'
70, 72, 74, 75, 76, 77, 78, 80
80
88
Median of the set = arithmetic mean of 75 and 85 = 80
It is 85, the middle value, between 80 and 90.
The variance of 90 75 72 74 80 82 58 48 60 64 = 161.3444
70, 72, 74, 75, 76, 77, 78, 80