It is 6.
A set of twelve numbers, with a mean value of 45/6, a median of 3, and a mode of 3.
0, 1, 4, 5, 6, 7, 8, 9, 9, 9, 11 mean = 6 and 3/11 median = 7 mode = 9
2/3 + 1/2 = 11/6 because:2/3 and 1/2 need to have the same denominator.So 2/3 and 1/2 becomes 4/6 and 3/6.When you add 4/6 and 3/6 together, you get 7/6...which equals 11/6
(5/6) * (1/10) + (2/3) / (4/11) = (5/6) * (1/10) + (2/3) * (11/4)= (1/12) + (11/6) = 1/12 + 22/12 = 23/12 or 111/12(5/6) * (1/10) + (2/3) / (4/11) = (5/6) * (1/10) + (2/3) * (11/4)= (1/12) + (11/6) = 1/12 + 22/12 = 23/12 or 111/12(5/6) * (1/10) + (2/3) / (4/11) = (5/6) * (1/10) + (2/3) * (11/4)= (1/12) + (11/6) = 1/12 + 22/12 = 23/12 or 111/12(5/6) * (1/10) + (2/3) / (4/11) = (5/6) * (1/10) + (2/3) * (11/4)= (1/12) + (11/6) = 1/12 + 22/12 = 23/12 or 111/12
That set has no mode.
6 is the mode.
Mode = 11Mode is thenumber in the list that is repeated more often.
What is the mode for 0 1 2 3 4 5 6 ?
none of the data repeat (they are all unique) so there is no mode.
The union of sets A and B is {2, 3, 6, 11, 16}
Median: 3 Mode: 1 Range: 6
If: |x|-3-6 = 2 Then: |x| = 2+3+6 = 11 If x > 0, then x = 11 If x < 0, then x = -11
The modes are 2, 3, 4, 5 and 6.
It is 6.
2*3=6 11-6=5 so the answer is 5
The answer is 6.