It is 52, the middle number when they are in order.
The median is the middle number, which is 52 in this case. You can see this by sorting the list: 49, 50, 51, 52, 53, 54, 55. Because of the distribution of number, it just so happens that the mean is also equal to 52. You find the mean by adding up the numbers, then divide this sum by [how many numbers], so this is 364 / 7 = 52.
The median is 51.
The numbers between 47 and 53 are 48, 49, 50, 51, and 52. These numbers form a consecutive sequence with a difference of 1 between each number. In mathematical terms, this sequence can be represented as {48, 49, 50, 51, 52}.
A single number, such has, 7152484654452062 can have only one mean, median, mode. And the range is 0.
It's the sum of the following probabilities: (4/52) * (36/51) * (35/50) * (34/49) * (33/48) = 1.81% (36/52) * (4/51) * (34/50) * (33/49) * (32/48) = 1.66% (36/52) * (35/51) * (4/50) * (33/49) * (32/48) = 1.71% (36/52) * (35/51) * (34/50) * (4/49) * (32/48) = 1.76% (36/52) * (35/51) * (34/50) * (33/49) * (4/48) = 1.81% total = 8.75%
349
44, 45, 46, 48, 49, 50, 51, 52 (including 52).
I am assuming that you are not replacing the cards in the deck after each draw. The probability of drawing no clubs = (52-13)/52*(51-13)/51*(50-13)/50*(49-13)/49 p= 39/52*38/51*37/50*36/49 ~= 0.3038 = 30.38% The probability of drawing at least one club = 1-0.3038=.6962 = 69.62%
It is 52, the middle number when they are in order.
The median of an even number of data is the average of the two data closest to the center of the sorted list. The sorted list is 43, 47, 49, 50, 50, 52, 52, 52, 58 & 60. The two numbers closest to the center of the list are 50 and 52, the average of which is 51.
If you don't replace the cards then it's: (4/52 x 3/51 x 2/50 x 1/49) Couldn't be bothered working it out
50 and 52 are the even numbers in this range, the odd numbers will be all the others, which is just the number 51.
52*51*50*49*48------------------------120answer is 2598960
Whole numbers: 45, 46, 47, 48, 49, 50, 51, 52, 53, 54
45, 46, 47, 48, 49, 50, 51, 52, 53, 54 Ten of them.
Whole numbers: 45, 46, 47, 48, 49, 50, 51, 52, 53, 54