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1/11 is the mole fraction of 58 g of KF dissolved in 180 g of water.

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What freezes faster sugar water or salt water?

sugar is a covalent compound where as salt is an ionic compound,so salt while dissolving in the water splits.This is mainly dependent of the 'total dissolved partical' concentration (mol/L):Sugar (C6H12O6): 1 mole particles per 180 g (for 1 mole sugar)Salt (NaCl) 2 mole particles per 58.5 g (for 1 mole salt) = 6 mole particles per about 180In water the freezing point will be lowered by 1.86oC per mole particles dissolved: So 180 g/L sugar: freeze at -1.86oCand 175.5 g/L salt freeze at -(6*1.86) = -11.2oCor 29.2 g/L salt will freeze at the same as 180 g suger: -1.86oC


A solution contains 180g of glucose C6H12O6 and 162 g of water What is the mole fraction of glucose?

To calculate the mole fraction of glucose, first find the moles of each component by dividing its mass by its molar mass. The molar mass of glucose (C6H12O6) is 180 g/mol. The moles of glucose is 180g / 180 g/mol = 1 mol. The moles of water is 162g / 18 g/mol = 9 mol. The total moles in the solution is 1 + 9 = 10 mol. The mole fraction of glucose is 1 mol / 10 mol = 0.1.


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