I think you mean mole ratio. It is usually represented as the coefficient or big number in a balanced chemical equation. N2 + 3H2 --> 2NH3 so the mole ratio of nitrogen to hydrogen is 1 : 3 or 1/3 and what you compare should be product / product or reactant / reactant
This deals with ratios and proportions. β± ββββββ β― ββββββ β° A : B = 2 : 3 B : C = 4 : 5. Now, to find A : B : C, we need to make the value of B equal in A : B ratio and B : C ratio. Here, Value of B in A : B ratio is 3; and B : C ratio is 4. LCM of 3 and 4 is 12. Therefore, we multiply 4 to the first ratio and 3 to the second ratio. A : B = 2 Γ 4 : 3 Γ 4 A : B = 8 : 12 Also, B : C = 4 Γ 3 : 5 Γ 3 B : C = 12 : 15 Now, we can combine A : B and B : C. A : B : C = 8 : 12 : 15.
the ratio of the savings of A B and C would be 56, 99, 69
In a circle Pi it the ratio of the circumference to the diameter. That is to say, if C is the cirumference and D is the diamter of any circle, we have: Pi=C/D
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In the balanced chemical equation for the formation of CO2 from C and O, the ratio of C to O is 1:2. Therefore, for 0.371 mole of C, you would need 0.742 moles of O to combine with it to form CO2.
Equal volumes (1 to 1) for each mole of any gas (doesn't matter what kind of).
C to O in the ratio 1 : 2.
The mole ratio between iodate (IOβ^-) and thiosulfate (SβOβΒ²-) ions is 1:3 in the reaction between the two ions, as seen in the balanced chemical equation of the reaction. 2SβOβΒ²- + IOβ^- β SβOβΒ²- + Iβ»
C : O are in the ratio 1 : 2
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The simplest formula based on the given moles would be BaSO4 (barium sulfate). This is determined by dividing each mole value by the smallest mole value (0.080 mole), resulting in a ratio of 1 Ba : 1 S : 4 O, which corresponds to BaSO4.
You probably meant to write 0.00390 mole H and not 0.0390 mole H. In that case the empirical formula is CH3O5
We assume 100 grams of compound and change % to grams. Get moles. 40 grams S (1 mole S/32.07 grams) = 1.247 60 grams O (1 mole O/16.0 grams) = 3.75 Now, the smallest mole value, sulfur, is 1. Divide the oxygen mole value by the sulfur mole value. 3.75 mole O/1.247 mole S = 3.00 SO3 ------- is the empirical formula
To find the empirical formula, we need to determine the ratio of each element in the compound. First, find the moles of each element: K = 0.104 mol C = 0.052 mol O = 0.156 mol Next, divide each mole value by the smallest mole value to get the ratio: K = 0.104 mol / 0.052 mol = 2 C = 0.052 mol / 0.052 mol = 1 O = 0.156 mol / 0.052 mol = 3 Therefore, the empirical formula is K2CO3.
It is 1:2:1
It is 1:2:1