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Any number that you choose can be the nth number. There are infinitely many rules, based on a polynomial of order 5, such that the first five numbers are as listed in the question. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
Using the principle of Occam's razor, the answer is
U(n) = 10*n
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What is nth term of this sequence 16 22 30 40?
6n+10
What is the nth term for 2 6 12 20 30 42?
n(n+1)
Find nth term for sequence 0 5 10 15 20 25 30 35?
This is an arithmetic progression. In general, If an A.P. has a first term 'a', and a common difference 'd' then the nth term is a + (n - 1)d. In the sequence shown in the question, the first term is 0 and the common difference is 5, therefore the nth term is, 0 + (n - 1)5. This can be rearranged to read : 5(n - 1) For example : the 7th term is 30 : 5(7 - 1) = 5 x 6 = 30.
What is the nth term for 3 30 300 3000?
3 x 10(n-1)
The nth term for 12 20 30 42 56 72?
The difference between the terms increases by 2 each time. 20-12=8 30-20=10 42-30=12 56-42=14 ... f(n)=(n+2)(n+3)
How do you find the nth term?
Say if you had the pattern 15 20 25 30 35 40 45 50 To find the nth term you have to see what the gap between the numbers is. In our case this is 5. Then you have to find out what the difference between the gap and the first number. In this sequence it is 10. So your answer would be..... 5n+10 That's how you find the nth term.
What is nth term of this sequence 16 22 30 40?
6n+10
What is the nth term for 2 6 12 20 30 42?
n(n+1)
Find nth term for sequence 0 5 10 15 20 25 30 35?
This is an arithmetic progression. In general, If an A.P. has a first term 'a', and a common difference 'd' then the nth term is a + (n - 1)d. In the sequence shown in the question, the first term is 0 and the common difference is 5, therefore the nth term is, 0 + (n - 1)5. This can be rearranged to read : 5(n - 1) For example : the 7th term is 30 : 5(7 - 1) = 5 x 6 = 30.
What is the nth term for 3 30 300 3000?
3 x 10(n-1)
The nth term for 12 20 30 42 56 72?
The difference between the terms increases by 2 each time. 20-12=8 30-20=10 42-30=12 56-42=14 ... f(n)=(n+2)(n+3)
What is the sequence if the nth term is 30-5n?
35
Why is the nth term n2 5 if the sequence is 6 9 14 21 30?
Clearly here the nth term isn't n25.
If the nth term of a sequence is 12n-6 what is the 8th term?
90
What is the nth term for 2 6 12 20 30?
here t1=2 t2=6 t3=12 t4=20 t5=30 the nth term is n(n+1) for t1 = 1(1+1)=2 for t2=2(2+1)=6 for t3=3(3+1)=12 for t4=4(4+1)=20 for t5=5(5+1)=30 for tn=n(n+1)
What is the 30th term of the sequence when the nth term is 3n-1?
When n=30, 3n-1 = 89 .
What is the nth term for 3 10 17 24 31?
You can see that all the numbers go up by 7. This means that the first part of the nth term rule for this sequence is 7n. Now, you have to find out how to get from 7 to 3, 14 to 10, 21 to 17 ... this is because we are going up in the 7 times table. To get from the seventh times table to the sequence, you take away four. So the answer is : 7n-4
