0
Any number that you choose can be the nth number. There are infinitely many rules, based on a polynomial of order 5, such that the first five numbers are as listed in the question. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
Using the principle of Occam's razor, the answer is
U(n) = 10*n
What else can I help you with?
What is nth term of this sequence 16 22 30 40?
6n+10
What is the nth term for 2 6 12 20 30 42?
n(n+1)
What is the nth term for 3 30 300 3000?
3 x 10(n-1)
The nth term for 12 20 30 42 56 72?
The difference between the terms increases by 2 each time. 20-12=8 30-20=10 42-30=12 56-42=14 ... f(n)=(n+2)(n+3)
What is the sequence if the nth term is 30-5n?
35
How do you find the nth term?
Say if you had the pattern 15 20 25 30 35 40 45 50 To find the nth term you have to see what the gap between the numbers is. In our case this is 5. Then you have to find out what the difference between the gap and the first number. In this sequence it is 10. So your answer would be..... 5n+10 That's how you find the nth term.
What is nth term of this sequence 16 22 30 40?
6n+10
What is the nth term for 2 6 12 20 30 42?
n(n+1)
How do you find the nth term for this pattern- 10 20 40 70 110 160?
To find the nth term of the pattern 10, 20, 40, 70, 110, 160, first observe the differences between consecutive terms: 10, 20, 30, 40, 50. These differences increase by 10 each time, suggesting a quadratic relationship. The nth term can be expressed as a quadratic equation: ( a_n = An^2 + Bn + C ). By solving a system of equations using the first three terms, we find ( a_n = 5n^2 + 5n ).
What is the nth term for 3 30 300 3000?
3 x 10(n-1)
The nth term for 12 20 30 42 56 72?
The difference between the terms increases by 2 each time. 20-12=8 30-20=10 42-30=12 56-42=14 ... f(n)=(n+2)(n+3)
What is the sequence if the nth term is 30-5n?
35
Find nth term for sequence 0 5 10 15 20 25 30 35?
The given sequence is an arithmetic sequence with a common difference of 5. To find the nth term of an arithmetic sequence, we use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term (a_1 = 0) and the common difference (d = 5). Therefore, the nth term of the sequence is (a_n = 0 + (n-1)5 = 5n - 5).
Why is the nth term n2 5 if the sequence is 6 9 14 21 30?
Clearly here the nth term isn't n25.
If the nth term of a sequence is 12n-6 what is the 8th term?
90
What is the formula for the nth term 22 14 6 -2 -10?
The given sequence is 22, 14, 6, -2, -10. To find the nth term, we observe that the sequence decreases by 8, 8, 8, and so on. This indicates a linear relationship with a common difference of -8. The formula for the nth term can be expressed as ( a_n = 22 - 8(n - 1) ), which simplifies to ( a_n = 30 - 8n ).
What is the nth term for 2 6 12 20 30?
here t1=2 t2=6 t3=12 t4=20 t5=30 the nth term is n(n+1) for t1 = 1(1+1)=2 for t2=2(2+1)=6 for t3=3(3+1)=12 for t4=4(4+1)=20 for t5=5(5+1)=30 for tn=n(n+1)
