This is an Arithmetic Series/Sequence.
In general the nth term, A(n) = a + (n - 1)d....where a is the 1st term and d is the common difference.
In this question, the 1st term equals 1 and the common difference is 4.
Then the nth term, A(n) = 1 + (n - 1) x 4 = 1 + 4n - 4 = 4n - 3.
The nth term is 4n - 3
2n^2-1
4 Four Qutro The correct answer is: The nth term is 4n + 1
The nth term is: 5-6n
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
The nth term is 4n - 3
2n^2-1
4 Four Qutro The correct answer is: The nth term is 4n + 1
The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).
It is: nth term = 35-9n
The nth term is: 5-6n
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
The nth term is: 3n+1 and so the next number will be 16
The given sequence is an arithmetic sequence with a common difference of 4 between each term. To find the nth term of an arithmetic sequence, we use the formula: nth term = a + (n-1)d, where a is the first term, d is the common difference, and n is the term number. In this case, the first term (a) is -3, the common difference (d) is 4, and the term number (n) is the position in the sequence. So, the nth term of the given sequence is -3 + (n-1)4 = 4n - 7.
The nth term is 6n+1 and so the next term will be 31
The given sequence is an arithmetic sequence with a common difference of 6. To find the nth term of this sequence, we can use the following formula: nth term = first term + (n - 1) x common difference where n is the position of the term we want to find. In this sequence, the first term is 1 and the common difference is 6. Substituting these values into the formula, we get: nth term = 1 + (n - 1) x 6 nth term = 1 + 6n - 6 nth term = 6n - 5 Therefore, the nth term of the sequence 1, 7, 13, 19 is given by the formula 6n - 5.
2n+5