This is an Arithmetic Series/Sequence.
In general the nth term, A(n) = a + (n - 1)d....where a is the 1st term and d is the common difference.
In this question, the 1st term equals 1 and the common difference is 4.
Then the nth term, A(n) = 1 + (n - 1) x 4 = 1 + 4n - 4 = 4n - 3.
I suspect that the first term should be "negative 3", ie the sequence is -3, 1, 5, 9, 13, 17, ... The nth term is 4n - 7
The nth term is 4n - 3
2n^2-1
4 Four Qutro The correct answer is: The nth term is 4n + 1
The nth term is: 5-6n
I suspect that the first term should be "negative 3", ie the sequence is -3, 1, 5, 9, 13, 17, ... The nth term is 4n - 7
The nth term is 4n - 3
2n^2-1
4 Four Qutro The correct answer is: The nth term is 4n + 1
It is: nth term = 35-9n
The nth term is: 5-6n
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
The nth term is: 3n+1 and so the next number will be 16
what will the eight number be. 1, 7, 13, 19, 25, 31 ...
The given sequence is an arithmetic sequence with a common difference of 6. To find the nth term of this sequence, we can use the following formula: nth term = first term + (n - 1) x common difference where n is the position of the term we want to find. In this sequence, the first term is 1 and the common difference is 6. Substituting these values into the formula, we get: nth term = 1 + (n - 1) x 6 nth term = 1 + 6n - 6 nth term = 6n - 5 Therefore, the nth term of the sequence 1, 7, 13, 19 is given by the formula 6n - 5.
2n+5
7n+4