There are infinitely many polynomials of order 5 that will give these as the first five numbers and any one of these could be "the" rule for the nth term. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one. And that assumes that the solution is a polynomial, not some other function of n.
The simplest solution for the nth term, based on a polynomial of degree 4, is
U(n) = (3*n^4 - 30*n^3 + 105*n^2 - 174*n + 272)/8
The nth term is 3n+7 and so the next number will be 22
2n+1
3n+7
The nth term is: 5-6n
The nth term of a sequence is the general formula for a sequence. The nth term of this particular sequence would be n+3. This is because each step in the sequence is plus 3 higher than the previous step.
The nth term is 3n+7 and so the next number will be 22
2n+1
3n+7
The nth term is: 5-6n
The nth term is 6n+1 and so the next term will be 31
The nth term of a sequence is the general formula for a sequence. The nth term of this particular sequence would be n+3. This is because each step in the sequence is plus 3 higher than the previous step.
It is: 2n+9
[ 25 - 6n ] is.
The nth term is: 2n+7 and so the next number will be 19
T(n) = 25 - 6n
The given sequence is an arithmetic sequence with a common difference of 6. To find the nth term of this sequence, we can use the following formula: nth term = first term + (n - 1) x common difference where n is the position of the term we want to find. In this sequence, the first term is 1 and the common difference is 6. Substituting these values into the formula, we get: nth term = 1 + (n - 1) x 6 nth term = 1 + 6n - 6 nth term = 6n - 5 Therefore, the nth term of the sequence 1, 7, 13, 19 is given by the formula 6n - 5.
Just add 3 each time and so the next number will be 19+3 = 22 The nth term is: 3n+1