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The series formula is, Tn = 2n2 - 3n + 10.
The sequence continues,
n = 5, T5 = 50 - 15 + 10 = 45
n = 6, T6 = 72 - 18 + 10 = 64
Notice that the difference in successive terms is increasing by 4 at each step.
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What is the nth term for 2 6 12 20 30 42?
n(n+1)
What is the nth term if the sequence goes 12 21 30 39 48?
Looks like 57: 12+9=21, +9=30, +9=39, +9=48, +9=57.
What is the nth term for 2 6 12 20 30?
here t1=2 t2=6 t3=12 t4=20 t5=30 the nth term is n(n+1) for t1 = 1(1+1)=2 for t2=2(2+1)=6 for t3=3(3+1)=12 for t4=4(4+1)=20 for t5=5(5+1)=30 for tn=n(n+1)
What is nth term of this sequence 16 22 30 40?
6n+10
What is the 30th term of the sequence when the nth term is 3n-1?
When n=30, 3n-1 = 89 .
What is the nth term for 2 6 12 20 30 42?
n(n+1)
What is the formula for the nth term for the sequence 12-21-30-39-48?
> since the value rises by nine at each step and the first term is 12 the formula for > the nth term is: 12+(n-1)*9 Which simplifies to Sn = 9n + 3
Why is the nth term n2 5 if the sequence is 6 9 14 21 30?
Clearly here the nth term isn't n25.
If the nth term of a sequence is 12n-6 what is the 8th term?
90
What is the nth term if the sequence goes 12 21 30 39 48?
Looks like 57: 12+9=21, +9=30, +9=39, +9=48, +9=57.
What is the nth term for 2 6 12 20 30?
here t1=2 t2=6 t3=12 t4=20 t5=30 the nth term is n(n+1) for t1 = 1(1+1)=2 for t2=2(2+1)=6 for t3=3(3+1)=12 for t4=4(4+1)=20 for t5=5(5+1)=30 for tn=n(n+1)
What is nth term of this sequence 16 22 30 40?
6n+10
What is the 30th term of the sequence when the nth term is 3n-1?
When n=30, 3n-1 = 89 .
The nth term for 12 20 30 42 56 72?
The difference between the terms increases by 2 each time. 20-12=8 30-20=10 42-30=12 56-42=14 ... f(n)=(n+2)(n+3)
What is the nth term of 2 9 16 23 30?
The nth term is 7n-5 and so the 6th term will be 37
How do you find the 30th term if nth term is 3n-1?
Just plug in 30 for n in 3n-1. The answer is 89.
What is the nth term for 3 30 300 3000?
3 x 10(n-1)
