The first differences are 5, 7, 9, 11, 13 and the second differences are 2,2,2,2 so the formula for the nth term is a quadratic.
tn = n2 + 2n - 2 (n = 1,2,3,...)
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∙ 14y agoThe nth term is 3n+7 and so the next number will be 22
+9
3n+7
5=22+12 8=22+22 13=22+32 20=22+42 29=22+52 40=22+62
t(n) = 6 + 8n
The nth term is 3n+7 and so the next number will be 22
+9
x2-3=n
3n+7
If you meant: 2 12 22 32 then the nth term = 10n-8
It is: nth term = 29-7n
5=22+12 8=22+22 13=22+32 20=22+42 29=22+52 40=22+62
The nth term is 5n-3 and so the next term will be 22
t(n) = 6 + 8n
the nth term is = 31 + (n x -9) where n = 1,2,3,4,5 ......... so the 1st term is 31+ (1x -9) = 31 - 9 =22 so the 6th tern is 31 + (6 x -9) = -23 Hope this helps
The nth term is -7n+29 and so the next term will be -6
The nth term is 22n and so the next number will be 5*22 = 110