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The first differences are 5, 7, 9, 11, 13 and the second differences are 2,2,2,2 so the formula for the nth term is a quadratic.

tn = n2 + 2n - 2 (n = 1,2,3,...)

Q: What is the nth term formula for 1 6 13 22 33 46?

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The nth term is 3n+7 and so the next number will be 22

+9

3n+7

5=22+12 8=22+22 13=22+32 20=22+42 29=22+52 40=22+62

t(n) = 6 + 8n

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The nth term is 3n+7 and so the next number will be 22

+9

x2-3=n

3n+7

If you meant: 2 12 22 32 then the nth term = 10n-8

It is: nth term = 29-7n

5=22+12 8=22+22 13=22+32 20=22+42 29=22+52 40=22+62

The nth term is 5n-3 and so the next term will be 22

t(n) = 6 + 8n

the nth term is = 31 + (n x -9) where n = 1,2,3,4,5 ......... so the 1st term is 31+ (1x -9) = 31 - 9 =22 so the 6th tern is 31 + (6 x -9) = -23 Hope this helps

The nth term is -7n+29 and so the next term will be -6

The nth term is 22n and so the next number will be 5*22 = 110