x2-3=n
28
9, 17, 25, 33, 41
22, and 21, and 33. 22 x 21 x 33, as a single entity is a measure of volume and cannot be converted to a linear measure.
Because of the pattern of plus 11 then minus ten I would go with 13 24 14
Well, start with any decimals u have, like 0.36. that is first. then the single digits, like 1, which is next. then 13, 23 and finally 33. since 13 is lower then 23, which is lower then 33. so the order is 0.36, 1, 13, 23, 33.
The given sequence is 1, 6, 13, 22, 33. To find the nth term, we can observe that the differences between consecutive terms are 5, 7, 9, and 11, which indicates that the sequence is quadratic. The nth term can be expressed as ( a_n = n^2 + n ), where ( a_n ) is the nth term of the sequence. Thus, the formula for the nth term is ( a_n = n^2 + n ).
The first differences are 5, 7, 9, 11, 13 and the second differences are 2,2,2,2 so the formula for the nth term is a quadratic. tn = n2 + 2n - 2 (n = 1,2,3,...)
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
It is: 10n-7 and so the next term is 43
28
18,23,28,33,... #1 is 18 #2 is 23 A difference of '5' Hence we can write '5n + x = 18 Where 'n' equals '1' Hence 5(1) + x = 18 5 + x = 18 Hence x = 18 - 5 = 13 So nth term is 5n + 13 NB Verification; does it work for the 4th term 5(4)+ 13 = 20 + 13 = 33 Which is true from above list.
44
It is increasing by 4 and the nth term is 4n+1
All you have to do is add 5 each time(x+5) It's 43
33