t(n) = 12*n + 5
To find the term number when the term value is 53 in a sequence, you need to know the pattern or formula of the sequence. If it is an arithmetic sequence with a common difference of d, you can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, and d is the common difference. By plugging in the values, you can solve for the term number.
tn = 2x2 + 3 where x = 1, 2, 3, ...
n=n3. The numbers given in the question are equal to 13, 23, 33, 43, 53.
12 + 32 + 53 = 97
t(n) = 12*n + 5
(Term)n = 59 - 2n
32 questions total 15 wrong number right / total= 32-15=17 so.... 17/32 = 0.53125 mulitply it by 100%= about 53% YOU GOT 53%
To find the term number when the term value is 53 in a sequence, you need to know the pattern or formula of the sequence. If it is an arithmetic sequence with a common difference of d, you can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, and d is the common difference. By plugging in the values, you can solve for the term number.
53% which would be a low E
tn = 2x2 + 3 where x = 1, 2, 3, ...
53*32 = 1696
53 * 32 = 1,696
Each term in the sequence is three times the previous term plus two, so the next term is 485.1 (3 x 1 + 2) 5 (3 x 5 + 2) 17 (3 x 17 + 2) 53 (3 x 53 = 2) 161 (3 x 161 + 2) 485
The factors of 17 are: 1, 17 The factors of 53 are: 1, 53
n=n3. The numbers given in the question are equal to 13, 23, 33, 43, 53.
12 + 32 + 53 = 97