To find the nth term of a sequence, we need to identify the pattern between the numbers. Looking at the differences between consecutive terms, we see that the differences are increasing by 9, 15, 21, and so on. This indicates that the sequence is following a pattern of adding consecutive odd numbers (1, 3, 5, 7, ...). Therefore, the nth term of this sequence can be expressed as n^2 + 7.
t(n) = 12*n + 5
To find the term number when the term value is 53 in a sequence, you need to know the pattern or formula of the sequence. If it is an arithmetic sequence with a common difference of d, you can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, and d is the common difference. By plugging in the values, you can solve for the term number.
tn = 2x2 + 3 where x = 1, 2, 3, ...
12 + 32 + 53 = 97
n=n3. The numbers given in the question are equal to 13, 23, 33, 43, 53.
t(n) = 12*n + 5
(Term)n = 59 - 2n
32 questions total 15 wrong number right / total= 32-15=17 so.... 17/32 = 0.53125 mulitply it by 100%= about 53% YOU GOT 53%
To find the term number when the term value is 53 in a sequence, you need to know the pattern or formula of the sequence. If it is an arithmetic sequence with a common difference of d, you can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, and d is the common difference. By plugging in the values, you can solve for the term number.
tn = 2x2 + 3 where x = 1, 2, 3, ...
53% which would be a low E
53*32 = 1696
To find the nth term of the sequence 11, 21, 35, 53, 75, 101, we can observe the differences between consecutive terms: 10, 14, 18, 22, and 26, which increase by 4 each time. This suggests that the sequence can be described by a quadratic function. The nth term can be represented as ( a_n = 5n^2 + 6n ), where n starts from 1. Thus, the nth term corresponds to this formula for values of n.
53 * 32 = 1,696
Each term in the sequence is three times the previous term plus two, so the next term is 485.1 (3 x 1 + 2) 5 (3 x 5 + 2) 17 (3 x 17 + 2) 53 (3 x 53 = 2) 161 (3 x 161 + 2) 485
The factors of 17 are: 1, 17 The factors of 53 are: 1, 53
12 + 32 + 53 = 97