135
540/4=135 540/10=54
If it's to be divisible by 5, it must end in 5 or 0. And if it's to be divisible by 3, adding the digits together must result in a multiple of 3.The smallest such number is 105; the largest is 990.Since 3 x 5 = 15, all three-digit multiples of 15 would qualify. Note that 105 = 15 x 7, and 990 = 15 x 66.
it is divisible by 3,5,9 i am fabulously sure
Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.
No, 135 is not an even number
A prime number is a number that is not divisible into whole numbers, except by itself and one. 135 is not a prime number as it is divisible by 5 with a ressulting quotient of 27.
No it is divisible by 5 at least 675/5 = 135 so also divisible by 135, and so on ...
the answer is 135
135
Numbers such as 135, 270, 405, and other multiples of 135.
135 135 / 3 = 45 135 / 5 = 27
A Prime number is a number that is not divisible into whole numbers, except by itself and one. 135 is not a prime number as it is divisible by 5 with a ressulting quotient of 27.
It is divisible by 5, and 15.
Any of its multiples including itself.
No, it does not go in evenly. To be divisible by 8 it would need to be divisible by two and 5 being and odd number is not.
It is: 135