17
Any number between 0 and 12 that you like. There is no need for the sides of the rectangle to be whole numbers!
Select any number, W, between 0 and 4 units.Consider a rectangle with width W and length, L = 8 - W units.Then the rectangle with dimensions L and W will have a perimeter of 16 units.Since there are infinitely many possible values for W, there are infinitely many possible answers to the question.
* It is unclear if the question is asking about two rectangles, each with a perimeter of 16, or two rectangles whose perimeters sum to 16. This answer assumes the former.Other than the 4x4 square, which coincidentally has both a perimeter and area of 16, some examples would be:1 x 7 rectangle : perimeter 16 in. , area 7 sq. in2 x 6 rectangle : perimeter 16 in., area 12 sq. in3 x 5 rectangle: perimeter 16 in., area 15 sq. inYou can calculate that for a given perimeter, the largest area is found in the square with a side measurement of P/4, i.e. the length and the width are the same.
What are the integers between 0 and 100 whose positive square roots are integers?
The sum of all integers between 45 and 90 is 3105.
17
17. A 4x4 rectangle has a perimeter of 16 units and an area of 16 square units. A 3x6 rectangle has a perimeter of 18 units and an area of 18 square units. The number 17 is halfway between 16 and 18.
perimeter is the measure around the figure; area is the measure within the figure formula: perimeter: length+length+width+width=perimeter (for square or rectangle) area: length times width= area ( for square or rectangle)
This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.
The formula for the perimeter of a rectangle is 2(L + W), where L is the length and W is the width. Then 16 = 2(L + W) : 8 = L + W. And L = W - 8, or W = L - 8 So, if you were dealing integers, you can choose any two numbers between 1 and 7 so that the numbers when added equal 8.
Yes, there is. The area of a rectangle sets a lower limit on its perimeter.If the area is A, then the quadrilateral shape with the smallest perimeter has sides of length sqrt(A). Therefore the minimum perimeter is 4*sqrt(A). The perimeter can have any value grater than that since the area of the rectangle can be maintained while making it thinner and longer and thus increasing its perimeter with out any upper limit.
Any number between 0 and 12 that you like. There is no need for the sides of the rectangle to be whole numbers!
Length is the distance between two different points. But perimeter is the distance between the same point. Really interesting. Isn't it? Perimeter of sqaure is 4 x side Perimeter of rectangle is 2 (length + breadth) Perimeter of triangle is a + b + c Perimeter of a circle is specially named as circumference.
There is no relationship between the perimeter and area of a rectangle. Knowing the perimeter, it's not possible to find the area. If you pick a number for the perimeter, there are an infinite number of rectangles with different areas that all have that perimeter. Knowing the area, it's not possible to find the perimeter. If you pick a number for the area, there are an infinite number of rectangles with different perimeters that all have that area.
No. Different rectangles, all with the same area, may have a different perimeter. Example:* A rectangle of 4 x 1 has an area of 4 square units, and a perimeter of 2(4+1) = 10. * A rectangle of 2 x 2 has an area of 4 square units, and a perimeter of 2(2+2) = 8. * A rectangle of 8 x 1/2 has an area of 4 square units, and a perimeter of 2(8 + 1/2) = 17. In fact, for any given area, you can make the perimeter arbitrarily large. On the other hand, you get the lowest perimeter if your rectangle is a square.
Picture a rectangle. The area is the space inside the lines. The perimeter is the distance around the lines.
The perimeter of a rectangle is not enough to determine its shape. Let B < 5.5 be the breadth of the rectangle and let L = (11 - B) be its length. Then perimeter = 2*(L + B) = 2*(11 - B + B) = 2*11 = 22. The choice of B was arbitrarily any number between 0 and 5.5. Therefore there are infinitely many shapes that will meet the requirements.