You zero out the variables in turn.
Y = 9(0) + 5
Y = 5
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9X + 5 = 0
9X = - 5
X = - 5/9
Can use these points to graph line.
( - 5/9, 5)
15
The equation 2x-5y=-1 has a graph that is a line. Every point on that line is an ordered pair that is a solution to the equation. So pick any real number x and plug it in. You will find a y and that pair (x,y) is an ordered pair that is a solution to this equation. For example, let x=0 Then we have -5y=-1so y=1/5 The ordered pair (0, 1/5) is a point on the line and a solution to the equation.
This first number in an ordered pair is x. And since x is always -5, all these work. (-5,0),(-5,1),(-5,2),(-5,3),(-5,4)
Tell whether the ordered pair (5, -5) is a solution of the system
Although no incomplete ordered pairs have been shown they can be readily solved.If x + y - 1 = 0, then x = 1 - y, also y = 1 - x.From the above formulae for x and y then any omissions can be completed.EXAMPLE : complete the ordered pairs (1) (7, y) and (2) (x, -4)(1) y = 1 - x = 1 - 7 = -6 : The ordered pair is thus (7, -6)(2) x = 1 - y = 1 -(-4) = 5 : The ordered pair is thus (5, -4)
The ordered pair is (5, 4).
There are an infinite number of ordered pairs. (-5, -7) is one pair
k
{-4,-5}
The lines intersect at (3, 5)
x = -6 y = -11
5x=4y=-20 x=-4 y=-5 (-4,-5) is the ordered pair
x = 5 and y = 4
These are equations of two straight lines. Provided the equations are not of the same or parallel lines, there can be only one ordered pair. So the ordered pair is - not are : (0.5, -1)
x = -3/5 and y = -24/5
x = 2 and y =1 so the lines intersect at (2, 1)
1. x + y = 62. -x + 3y = -2Adding 1. to 2. gives:3. 4y = 4y = 1Substitutuing y = 1 into 1. gives:x + 1 = 6x = 5Writing our ordered pair in the form of (x,y) we have (5, 1).