2400 + 160 + 8
They are 2400, 160 and 8.
Bu u
8+160+2400
321 ÷ 40 = 8 remainder 1 (therefore, not evenly).
Single digits don't have partial products. 8 x 6 = 48
34 x 28 = 34 x (20 + 8) First partial product is: (30 + 4) x 8 = 240 + 32 Second partial product is: (30 + 4) x 20 = 600 + 80 Sum of partial products = total product = 600 + 240 + 80 + 32 = 952
The partial products are 40*20 + 40*8 + 20*2 + 2*8 = 800 + 320 + 40 + 16 = 1176.
It is 8 times 1 = 8
321 ÷ 40 = 8 remainder 1 (therefore, not evenly).
Single digits don't have partial products. 8 x 6 = 48
34 x 28 = 34 x (20 + 8) First partial product is: (30 + 4) x 8 = 240 + 32 Second partial product is: (30 + 4) x 20 = 600 + 80 Sum of partial products = total product = 600 + 240 + 80 + 32 = 952
The partial products are 40*20 + 40*8 + 20*2 + 2*8 = 800 + 320 + 40 + 16 = 1176.
The product for 4 times 8 is 32. The product is the answer you get when you multiply numbers together.
The partial products for 57 times 48 are: 48 multiplied by 7, which equals 336 48 multiplied by 50, which equals 2,400 Adding these two partial products together gives a total product of 2,736.
4 x 40 = 160 4 x 8 = 32 160 + 32 = 192 4 x 48 = 192
The product of 137 times 8 is 1080.
It is 8 times 1 = 8
64
48, product means times
The octal equivalent of the decimal number 321 is 501.