19 For partial-products you break the numbers up into different problems * 6 like 9 times 6, and 6 times 10, then you just add the two sums together ------------- to get the whole sum 9*6= 54 6*10= 60 60+54= 114
6 x 80 = 480 6 x 5 = 30
i think 6 and 500
Single digits don't have partial products. 8 x 6 = 48
80*6, 9*6
They are: 30*50, 30*7, 6*50 and 6*7.
To find 513 times 46, you can break it down into two partial products: 513 times 40 and 513 times 6. This gives you 513 × 40 = 20,520 and 513 × 6 = 3,078. Adding these two partial products together, you get 20,520 + 3,078 = 23,598. Thus, 513 times 46 equals 23,598.
6 x 80 = 480 6 x 5 = 30
the partial products for 12 and 3 30 and 6 :)
To find the partial products for 56 and 31, you can break down each number into its place values. For 56, this is 50 and 6; for 31, it's 30 and 1. The partial products are calculated as follows: 50 × 30 = 1500, 50 × 1 = 50, 6 × 30 = 180, and 6 × 1 = 6. Thus, the partial products are 1500, 50, 180, and 6.
6
i think 6 and 500
Single digits don't have partial products. 8 x 6 = 48
80*6, 9*6
the partial product for 51 and 36 300,6,1000,500,and 30 :)
They could be 1200, 60 and 6.
They are: 30*50, 30*7, 6*50 and 6*7.
3.16666 x 6 = 19