They are:
30*50, 30*7, 6*50 and 6*7.
how to find the partial products of a number
The partial products for 734X29 are 6,606 and 14,680.
50 x 30 = 1500 50 x 6 = 300 30 x 1 = 30 6 x 1 = 6
700 and 210 are the answers to partial products of 77 times 30
29 x47=
The partial products for 57 times 48 are: 48 multiplied by 7, which equals 336 48 multiplied by 50, which equals 2,400 Adding these two partial products together gives a total product of 2,736.
how to find the partial products of a number
The partial products for 734X29 are 6,606 and 14,680.
50 x 30 = 1500 50 x 6 = 300 1 x 30 = 30 1 x 6 = 6
50 x 30 = 1500 50 x 6 = 300 30 x 1 = 30 6 x 1 = 6
Partial products of 87 times 65 would be 80 x 60 and 80 x 5 and 7 x 60 and 7 x 5. Partial products allow for the multiplication of whole numbers.
36% means 36/100 = 0.36 0.36X = 57 X = 158.3 -----------------
To find the partial products of 77 x 30, we can break down the numbers into their place values. We can express 77 as 70 + 7 and 30 as 30. The partial products are: 70 x 30 = 2100 and 7 x 30 = 210. Thus, the partial products of 77 x 30 are 2100 and 210.
700 and 210 are the answers to partial products of 77 times 30
80 + 24
90 and 54
32 and 160