126
72
5 goes into 630 126 times.
The LCM of 2, 5, 7 and 9 is 630.
Well since it ends with a 5, u usually should round up. So the answer should be 630
214 divided by 5 equal in partial quotients = 42.8
485 divided by 5 equal in partial quotients = 97
120 divided by 3 = 40 15 divided by 3 = 5 135 divided by 3 = 45
Example: 135 divided by 3 120 divided by 3 = 40 15 divided by 3 = 5 135 divided by 3 = 45
126
630 divided by 5 equals 126.
If you have a ratio of polynomials in which the denominator can be factorised, then partial quotients or partial fractions are form an equivalent expression but one in which the denominators of the terms are those fractions.For example, suppose you start with (2x + 5)/(x^2 + 3x + 2)The denominator can be factorised into (x + 1)*(x + 2)So the partial fractions are 3/(x + 1) - 1/((x + 2).
72
9.8
5% of 630 = 31.5= 5%/100% * 630= 5/100 * 630= 0.05 * 630= 31.5
Every number besides 0 can be safely divided into 3, 5, and 7, although most of the resultant quotients will have a non-zero remainder. If you require all three quotients to have a remainder of zero, then the divisor must be the reciprocal of any non-zero integer. If you require the divisor itself to be a non-zero integer, then there are only two numbers that can be divided into 3, 5, and 7 without a remainder, 1 and -1.
$395.20/5