you divide by three each time
729\3=243\3=81\3=27
3, 9, 27, 81, 243, 729, 2187, 6561, 19683, 59049
1 x 729, 3 x 243, 9 x 81, 27 x 27
9 3 1
1 x 729, 3 x 243, 9 x 81, 27 x 27
243, -729, 2187
1, 3, 9, 27, 81, 243, 729
They are powers of 3. 729 = 36 243 = 35 81 = 34 27 = 33 9 = 32 3 = 31
1, 3, 9, 27, 81, 243, 729 | 1 x 729, 3 x 243, 9 x 81, 27 x 27.
1, 3, 9, 27, 81, 243, 729: (1 x 729, 3 x 243, 9 x 81, 27 x 27)
729 is divisible by 1, 3, 9, 27, 81, 243, 729.
1, 3, 9, 27, 81, 243, 729.
The factors of 729 are: 1 3 9 27 81 243 729
The factors of 729 are: 1 3 9 27 81 243 729
729
All these will result in 729: 1 x 729, 3 x 243, 9 x 81, 27 x 27, 81 x 9, 243 x 3, 729 x 1
All Factors of 729:1, 3, 9, 27, 81, 243, 729
3 = 3^(1) 9 = 3(2) ??? = 3^(3) 81 = 3^(4) 243 = 3^(5) 729 = 3^(6) There are TWO missing numbers !!! They are 3^(3) = 27 & 3^(0) = 1 1 = 3^(0) 3 = 3^(1) 9 = 3(2) 27 = 3^(3) 81 = 3^(4) 243 = 3^(5) 729 = 3^(6)