25%
.850
25 percent of a dollar is 25 cents.
To find 25 percent of 3400, you can multiply 3400 by 0.25. This calculation gives you 850, which is 25 percent of 3400. In other words, 25 percent of 3400 is equal to 850.
The increase is 32 percent. (8/25)
1,100 increased by 25 percent is 1,375
With 25ml methanol and 75ml water, there is 100ml in total. So there is 25/100 = 25% by volume methanol.
The sodium methoxide reacts with the water to produce sodium hydroxide an methanol.
50% methanol will damage the membrane more than 25% acetone. we did the lab.
If the concentration of alcohol and water solution is 25 percent alcohol by volume, the volume of alcohol in a 200 solution is 50.
The total volume of the solution is 48 mL + 144 mL = 192 mL. The percent by volume of ethanol is calculated as (volume of ethanol / total volume of solution) * 100%. Plugging in the values, we get (48 mL / 192 mL) * 100% = 25%. So, the solution contains 25% ethanol by volume.
To produce 1L of 10% ammonia solution from 25% ammonia solution, you need to dilute the 25% solution by adding a calculated amount of water. To do this, you can calculate the volume of the 25% solution needed and the volume of water needed using the formula: C1V1 = C2V2, where C1 is the initial concentration (25%), V1 is the initial volume, C2 is the final concentration (10%), and V2 is the final volume (1L).
To make 25% sulfuric acid from 98% sulfuric acid, you can dilute the concentrated acid by adding distilled water. The formula for dilution is C1V1 = C2V2, where C1 is the initial concentration, V1 is the volume of initial solution, C2 is the final concentration (25%), and V2 is the final volume of the diluted solution. Use this formula to calculate the volume of 98% sulfuric acid and water needed to achieve a 25% solution.
The volume will be 960 cubic units.
To calculate the volume percent concentration of propanol in the solution, we first need to find the total volume of the solution. This would be the sum of the volumes of propanol and water: 100 mL + 300 mL = 400 mL. The volume percent concentration of propanol in the solution is then calculated by dividing the volume of propanol by the total volume of the solution and multiplying by 100: (100 mL / 400 mL) * 100 = 25%. Therefore, the propanol concentration in the solution is 25% (v/v).
% V / V (percentage of volume per volume) =? V1 (solute volume) = 25 mL V (volume of the solution) = solute + solvent = 25 mL + 45 mL = 70 mL We apply the data to the formula of volume percentage of the solute per volume of solution, we will have:
Out of total volume of 1400Km3 of available water in the world, about 3.0 percent is only usable fresh water out of which 25 percent is only is ground water on earth. Out of this total 25 percentage of groundwater, 14% is at depth > 1KM and remaining 11% is at depth < 1 KM.
The solubility of sodium chloride in methanol is 14 g/kg at 25 0C.